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Sedbober [7]
2 years ago
8

Instructions: Find the volume of each figure. Round your answers to the nearest tenth, if necessary.

Mathematics
1 answer:
Maslowich2 years ago
7 0

A cone is a <em>3-dimensiona</em>l shape that consists of a <u>circular</u> or <u>flat</u> surface and a <u>curved</u> side. Thus the <em>volume</em> of the given cone is 4.1 mi.^{3}

A cone is a<em> 3-dimensiona</em>l shape that consists of a <u>circular</u> or <u>flat</u> surface and <u>curved</u> side. Its <em>volume</em> can be determined by;

The <u>volume</u> of a <u>cone </u>= \frac{1}{3} \pir^{2}h

where r is the <u>radius</u> of its <u>flat</u> surface, and h is its <em>height</em>.

From the given question, we have to <u>determine</u> the value of h using the <u>Pythagoras</u> theorem.

Such that;

/Hyp/^{2} = /Adj 1/^{2} + /Adj 2/^{2}

4^{2} = h^{2} + 1^{2}

16 = h^{2} + 1

h^{2} = 15

h = \sqrt{15}

Thus the<em> volume </em>of the<em> cone</em> = \frac{1}{3} \pir^{2}h

                             =  \frac{1}{3}x \frac{22}{7} x 1^{2}x    \sqrt{15}

                             = 4.0574

Therefore the <u>volume</u> of the given<em> cone</em> is 4.1 mi.^{3}

For more clarifications on the volume of a cone, visit: brainly.com/question/26936929

#SPJ1

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