The fraction of the course 7/8 is male on the maths course at university.
Step-by-step explanation:
There are 7 times as many males as females on the maths course at University. Let's suppose we have 10 females in the course.If we have 10 females, the males should be 7 times; it means with 10 females males should be 70 males.
Now, we have the number of males (M) - 70 and females (F) - 10. We can calculate the fraction of the male (%M) in the course.
%M = M/(M+F)
%M = 70 / (70 +10)
% M = 70/80
%M = 7/8.
Finally, we can conclude that the fraction of the course 7/8 are male on the maths course at university.
This is a geometric sequence with a common ratio of 2
an = a1 * r^(n - 1) n = term to find = 21 a1 = first term = 0.05 r = common ratio = 2 now we sub a21 = 0.05 * 2^(21 - 1) a21 = 0.05 * 2^20 a21 = 0.05 * 1048576 a21 = 52428.80 <==== after working 21 days
