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atroni [7]
3 years ago
14

There are 7 times as many males as females on the maths course at university. What fraction of the course are male? Give your an

swer in its simplest form.
Mathematics
1 answer:
podryga [215]3 years ago
3 0

Answer:

The fraction of the course 7/8 is male on the maths course at university.

Step-by-step explanation:

There are 7 times as many males as females on the maths course at University. Let's suppose we have 10 females in the course.If we have 10 females, the males should be 7 times; it means with 10 females males should be 70 males.

Now, we have the number of males (M) - 70 and females (F) - 10. We can calculate the fraction of the male (%M) in the course.

%M = M/(M+F)

%M = 70 / (70 +10)

% M = 70/80

%M = 7/8.

Finally, we can conclude that the fraction of the course 7/8 are male on the maths course at university. 

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Gambling at a slot machine is an example of which reinforcement schedule?
gogolik [260]

Answer:

d. Variable ratio

Step-by-step explanation:

We are asked to determine that gambling at a slot machine is an example of which reinforcement schedule.

Let us see our given choices one by one.

a. Fixed ratio

We know that in fixed ratio schedule, reinforcement is delivered after the completion of a number of responses. An example of fixed ratio is a reward to every 6th response.

b. Fixed interval

We know that in fixed interval schedule the first response is rewarded only after a specified amount of time has elapsed. An example of fixed interval schedule is weekly paycheck.

c. Variable interval

We know that in variable interval schedule, the reinforcement is delivered at changing and unpredictable intervals of time.

d. Variable ratio

In variable ratio schedule, a response is reinforced after an unpredictable number of responses. Gambling and lottery are examples of variable ratio.

Therefore, option 'd' is the correct choice.

8 0
3 years ago
A dinner plate has a circumference of 106.76 cm. What is the area of the dinner plate? Use = 3.14.
Sphinxa [80]
C=2pr,  r=c/(2p)

a=pr^2, using r found above we get:

a=p(c^2/(4p^2))

a=(c^2)/(4p), since c=106.76 and we approximate pi as 3.14

a=(106.76^2)/(4*3.14)

a=11612.2176/12.56 cm^2

a≈924.54 cm^2  (to nearest one-hundredth of a square cm)
3 0
3 years ago
I sent a photo of question pls help
statuscvo [17]
Answer should be 2, 7/2 hopefully this helped ^^
3 0
3 years ago
(03.01 LC)<br><br> What is the length of leg y of the right triangle? (1 point)
EastWind [94]

Answer:

<h2>A</h2>

Step-by-step explanation:

The complete question is

What is the length of leg y of the right triangle?

A right triangle with hypotenuse 26 and legs 24 and y

  • 10
  • 14
  • 24
  • 26

We need to use the Pythagorean Theorem, where h=26 and x=24,

h^{2} =x^{2} +y^{2}\\ 26^{2}=24^{2}+y^{2}\\y=\sqrt{26^{2}-24^{2}}\\ y=\sqrt{676-576}\\ y=\sqrt{100}\\ y=10

Therefore, the right answer is A. The length of the missing leg is 10 units.

4 0
3 years ago
Braden biked 10 8/9 miles on Monday. On Tuesday, he biked 3/ 4 as far as Monday. How many total miles did he bike over the two d
torisob [31]

Answer:

19 1/18 miles.

Step-by-step explanation:

For Tuesday's ride we need to multiply 10 8/9 by 3/4.

10 8/9 = (9*10+8) / 9 =  98/9 miles.

98 / 9  * 3/4

= 98/3 * 1/4

49/6

= 8 1/6 miles.

Total miles over 2 days = 10 8/9 + 8 1/6

= 18 + 8/9 + 1/6

= 18 +  48/54 + 9/54

= 18 57/54

= 19 3/54

= 19 1/18 miles.

5 0
3 years ago
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