First find the secant line. The slope of the secant line through
(when
) and
(when
) is the average rate of change of
over the interval
:
The tangent line to
will have a slope determined by the derivative:
Both the secant and tangent will have the same slope when
, or when
.
Answer:
15.83
Step-by-step explanation:
13.11 / 100 = 0.1311
0.1311*5=5%=0.6555
13.11+0.6555=13.7655
13.7655/100=0.137655 * 15 -->15%=2.064528
13.7655+2.064528=15.830325
Answer:
Step-by-step explanation:
You have to find the slope
Slope= y₂ - y₁ / x₂-x₁
A(3, -3), B(2, 1)
Slope of AB m₁ = 1-[-3] / 2-3 = 1+3 / -1 = 4/-1 = -4
B(2, 1) ; C(7, -2)
slope of BC m₂= -2-1 / 7-2 = -3/5
A(3, -3) ; C(7, -2)
Slope of AC m₃ = -2-[-3] / 7-3 = -2+3 / 4 = 1/4
m₁ * m₃ = -4 * (1/4) = -4/4 = -1
When the product of slope is (-1), then two lines are perpendicular.
So AB and AC are perpendicular. Δ ABC is a right-angled triangle
y = 23/8
Please correct me if I'm wrong!! :)