Answer:
5.65mg of the isotope remains
Explanation:
The radioactive decay follows the equation:
Ln[A] = -kt + ln[A]₀
<em>Where [A] is amount of the isotope after time t, k is decay constant, and [A]₀ is initial amount of the isotope.</em>
k = ln 2 / Half-life
k = ln 2 / 3.82 days
k = 0.18145days⁻¹
Replacing:
Ln[A] = -0.18145days⁻¹*10.1days + ln[35.3mg]
ln[A] = 1.7312
[A] = 5.65mg of the isotope remains
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Answer:
14 g
Explanation:
First, we have to calculate the partial pressure of N₂. We know that the air is 80% nitrogen by volume, which, for a gas mixture, means that the mole fraction of N₂ is 0.80.
We can calculate the partial pressure of N₂ (pN₂) using the following expression:
pN₂ = P . x(N₂)
where,
P is the total pressure
x(N₂) is the mole fraction of N₂
pN₂ = 1.1 atm . 0.80 = 0.88 atm
Then, we can calculate the moles of N₂ using the ideal gas equation.
Considering that the molar mass of N₂ is 28.01 g/mol, the mass of N₂ is:
Answer:
EVERYTHING!!!! Okay, but really he didn't show in his model that there is different charges distributed in the atom.
Explanation: