a plant that has flowers and fruits
mol CO₂ = 9.6
mol N₂ = 4.8
mol O₂ = 0.8
mol H₂O = 8
<h3>Further explanation</h3>
Reaction
4C₃H₅O₉N₃ → 12CO₂ + 6N₂ + O₂ + 10H₂O
mol CO₂

mol N₂

mol O₂

mol H₂O

Answer:
Molar solubility of AgBr = 51.33 × 10⁻¹³
Explanation:
Given:
Amount of NaBr = 0.150 M
Ksp (AgBr) = 7.7 × 10⁻¹³
Find:
Molar solubility of AgBr
Computation:
Molar solubility of AgBr = Ksp (AgBr) / Amount of NaBr
Molar solubility of AgBr = 7.7 × 10⁻¹³ / 0.150
Molar solubility of AgBr = 51.33 × 10⁻¹³
Answer:
1.They are reliable.
2.They dont vary from person to person