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2 years ago

What indicates that two objects are in thermal equilibrium?

Chemistry

1 answer:

Leona [35]2 years ago

4 0

Answer:

Explanation:

equilibrium happens when two things are in complete balance and thermal is in reference to heat so two things are in thermal equilibrium once they have the same temperature.

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Sentences with word carcasses

xenn [34]

The deer carcasses lay on the side of the road on the highway.

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3 years ago

Read 2 more answers

If 2.4 g of n2 gas has a volume of 0.40 l and a pressure of 6.6 atm , what is its kelvin temperature?

Nesterboy [21]

To solve for the absolute temperature, we assume ideal gas behaviour so that we use the equation:

PV = nRT

or T = PV / nR

So calculating:

T = [6.6 atm * 0.40 L] / [(2.4g / 28g/mol) * 0.08205746 L atm / mol K]

8 0

3 years ago

A reaction between 46 grams of sodium and 71 grams of chlorine formed table salt and heat.

vazorg [7]

Answer:

d. 117 grams

Explanation:

The mass of the table salt produced will be 117 grams.

Chemical reactions obey the law of conservation of mass. In this regard, matter is neither created nor destroyed in the course of a chemical reaction. It is expected that the mass of the reactants and products remain the same.

The reaction expression:

2Na + Cl₂ → 2NaCl

So, mass of sodium = 46g

mass of chlorine formed = 71g

Mass of NaCl = 46 + 71 = 117g

7 0

3 years ago

What element is represented in this model if the atomic number is 3?<br> This is science

Readme [11.4K]

Answer:

Lithium (Li)

Explanation:

Lithium has an atomic number of 3

6 0

3 years ago

Find the pH of a 0.010 M HNO2 solution.

lidiya [134]

Data:
Molar Mass of HNO2
H = 1*1 = 1 amu
N = 1*14 = 14 amu
O = 3*16 = 48 amu
------------------------
Molar Mass of HNO2 = 1 + 14 + 48 = 63 g/mol

M (molarity) = 0.010 M (Mol/L)

Now, since the Molarity and ionization constant has been supplied, we will find the degree of ionization, let us see:
M (molarity) = 0.010 M (Mol/L)
Use: Ka (ionization constant) = $5.0*10^{-4}$
$\alpha^2 (degree\:of\:ionization) = ?$

$Ka = M * \alpha^2$
$5.0*10^{-4} = 0.010* \alpha^2$
$0.010\alpha^2 = 5.0*10^{-4}$
$\alpha^2 = \frac{5.0*10^{-4}}{0.010}$
$\alpha^2\approx500*10^{-4}$

$\alpha\approx\sqrt{500*10^{-4}}$
$\alpha \approx 2.23*10^{-3}$

Now, we will calculate the amount of Hydronium [H3O+] in nitrous acid (HNO2), multiply the acid molarity by the degree of ionization, we will have:

$[ H_{3} O^+] = M* \alpha$
$[ H_{3} O^+] = 0.010* 2.23*10^{-3}$
$[ H_{3} O^+] \approx 0.0223*10^{-3}$
$[ H_{3} O^+] \approx 2.23*10^{-5} \:mol/L$

And finally, we will use the data found and put in the logarithmic equation of the PH, thus:

Data:
log10(2.23) ≈ 0.34
pH = ?
$[ H_{3} O^+] = 2.23*10^{-5}$

Formula:
$pH = - log[H_{3} O^+]$

Solving:
$pH = - log[H_{3} O^+]$
$pH = -log2.23*10^{-5}$
$pH = 5 - log2.23$
$pH = 5 - 0.34$
$\boxed{\boxed{pH = 4.66}}\end{array}}\qquad\quad\checkmark$

Note:. The pH <7, then we have an acidic solution.

6 0

4 years ago