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Strike441 [17]
4 years ago
12

Explain how NOTHING is ZERO, but ZERO is more than NOTHING?

Chemistry
1 answer:
AleksAgata [21]4 years ago
4 0

Answer:

Nothing can be zero, but zero isn't nothing. If someone asks you if you have money and you say "I've got nothing!" when you actually don't have a cent, then you have zero money. However, zero is a number, so it itself is something, therefore more than nothing. So technically, you do have something.

When zero is on a number line, you could classify it as nothing, but it is the number between 1 and -1. Hypothetically speaking, if you took the zero away, wouldn't the number line be the same?

Zero isn't positive or negative. The number zero on a graph, or in a coordinate can tell you where something is. Zero can be a word to describe if something is existent, or non-existent.

Okay, my brain hurts.

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Indicate which of the following statements is FALSE.a. Covalent bonds connect nucleotides in a strand; noncovalent interactions
LenaWriter [7]

Answer:

The false statement is d Avery,Macleod and McCarty showed that DNA is the genetic information of cells and RNA is the genetic information in the viruses .

Explanation:

Avery,Macleod and MacCarty showed that DNA is the genetic material of the cell.

     On the other hand Fraenkel, Conrat and Sanger carried out their experiment on tobacco mosaic virus to prove that RNA act as genetic material in some viruses.

8 0
4 years ago
Sugar is stirred into water tp form a solution what names to we give to the sugar and water
Nina [5.8K]
Your answer would be, Sugar is the solute, and water is the solvent. a solution is the mixture of two, or more substances.




Hope that helps!!!
7 0
4 years ago
150.0 grams of an isotope with a half-life of 36.0 hours is present at time zero. How long will it take
leonid [27]

Given :

Initial mass , a = 150 gm .

Half time ,

t_{\dfrac{1}{2}}=36 \ hours.

Final mass , x = 18.75 gm .

To Find :

The time taken to decay 18.75 gm .

Solution :

We know , time taken is given by :

t=\dfrac{1}{k}\times ln(\dfrac{a}{a-x})

Here , k is a constant given by :

k=\dfrac{0.693}{t_{\dfrac{1}{2}}}\\\\\\k=\dfrac{0.693}{36}

Putting all given value in above equation :

We get :

t=\dfrac{36}{0.693}\times ln(\dfrac{150}{150-18.75})\\\\t=6.94\ hours

Therefore , time taken is 6.94 hours .

Hence , this is the required solution .

5 0
4 years ago
Decide which of the following statements are True and which are False about equilibrium systems:A large value of K means the equ
ivanzaharov [21]

Answer:

a. True

b. False

c. True

d.  False

e. False

Explanation:

A. (true) The equilibrium constant K is defined as

\frac{Products}{reagents}

In any case  

aA +Bb ⇌ Cd +dD

where K is:

K= \frac{[C]^{c}[D]^{d}}{[A]^{a}[B]^{b}}

A large value on K means that the concentration of products is bigger than the concentrations of reagents, so the forward reaction is favored, and the equilibrium lies to the right.

B. (False) When we work with gases, we use partial pressure to make calculations in the equilibrium, so we estimate Kp as:

Kp= \frac{(P_{C})^{c}(P_{D})^{d}}{(P_{A})^{a}(P_{B})^{b}}

Using the ideal gas law, we can get a relationship between K and Kp  

Pv=nRT where P=\frac{n}{v}*RT we know that \frac{n}{v} is the molar concentration. When we replace P in the expression for Kp we get:

Kp= \frac{[C]^{c}*(RT)^{c}[D]^{d}*(RT)^{d}}{[A]^{a}*(RT)^{a}[B]^{b}*(RT)^{b}}

Reorganizing the equation:

Kp= \frac{[C]^{c}[D]^{d}}{[A]^{a}[B]^{b}}*\frac{(RT)^{c+d}}{(RT)^{a+b}}

We can see K in the expression  

Kp= K*(RT)^{c+d-a-b}

Delta n = c+d-a-b

Kp= K*(RT)^{delta n}

For the reaction  

H_{2}(g) + F_{2}(g)-- equilibrium---2HF(g)

Delta n = 2-1-1=0

Kp= K*(RT)^{0}

So Kp=K in this case.

C. (true) The value of K just depends on the temperature that’s why changing the among of products won’t have any effect on its value.  

D. (false) as we can see this reaction involve a heterogeneous system with solids and gases. For convention the concentration for solids and liquids can be considered constant during the reaction that’s why they’re not include in the calculation for the equilibrium constant. Taking this into account the expression for the equilibrium for this reaction is:

CaCO_{3}(s)---equilibrium----CaO(s) + CO_{2}(g)

K= [CO_{2}]

So we can see that [CaCO_{3}] is not include in the expression.  

E. (False) The equilibrium is defined as the point where the rate of the forward reaction is the same to the rate of the reverse reaction. The value of K is telling you which reaction is favored but the rate of both reactions is the same in this point. (see picture)  

3 0
3 years ago
A chemical reaction has two elements as reactants. Which type of reaction might occur?
Elden [556K]
That should be a synthesis reaction
3 0
3 years ago
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