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Maurinko [17]
1 year ago
10

Please help quick what is the answer thank you

Mathematics
2 answers:
Gennadij [26K]1 year ago
8 0

Answer:

y= -3x+4

Step-by-step explanation:

y=mx+c

m= y2-y1 ÷ x2-x1

m= -3

y=-3x+c

7=-3(-1)+c

c=4

y=-3+4

notka56 [123]1 year ago
5 0
Answer: y= -3x + 4
Explanation: As the general equation of line is y= mx + c where m is the slope of the line and c is the y intercept.
=> for m we need to find the slope of line which is y2 - y1/ x2 - x1
=> 7-1/ -1-1 = 6/-2 = -3
and as we can in the diagram the y intercept is 4
that means our equation for the given line is y = -3x + 4.
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stacey made 8 necklaces in 48 minutes. nick made 4 necklaces in 24 minutes. is the rate at which they made necklaces equivalent.
Bingel [31]

Answer:

Yes.

Step-by-step explanation:

Divide - 48 / 8 which equals 6. Stacey makes 6 necklaces in 1 minute. Then, do 24 / 4. This also equals 6. Nick makes 6 necklaces in one minute. Therefore, their speed is equivalent.

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2 years ago
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How do I solve this using long polynomial division?
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Eduardwww [97]

Answer:

13 x 9 x 5

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6 0
2 years ago
The function h(t) = -16t^2 + 16t represents the height (in feet) of a horse (t) seconds after it jumps during a steeplechase.
Vladimir79 [104]
A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.

h'(t) = -32t + 16

When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.

-32t + 16 = 0

-32t = -16

t = 0.5 seconds

b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.

h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet

If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.

c.) We know that the horse is in the air whenever h(t) is greater than 0. 

-16t^2 + 16t = 0

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t = 0 and 1

So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.
7 0
3 years ago
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