Answer:
A vector perpendicular to two given vectors, u and v, and having magnitude equal to the product of the magnitudes of the two given vectors multiplied by the sine of the angle between the two given vectors, usually represented by u × v.
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
Front and back (triangles
There are two triangles (right angle).
They are found by multiplying the 2 legs together.
Area = 1/2 * b * h
b = 4
h = 3
Area = 1/2 * 4 * 3
Area = 6
But there are 2 of them so the Area = 12
Left face (slanted.
The hypotenuse of the right triangle is 5
a^2 + b^2 = c^2
a = 3
b = 4
c = ?
3^2 + 4^2 = c^2
9 + 16 = c^2
c^2 = 25
sqrt(c^2) = sqrt(25)
c = 5
The front face is 5* 7 = 35
Left side
w = 3
L = 7
Area 3 * 7 = 21
Bottom
L = 7
w = 4
Area = L * W
Area = 7 * 4 <u> 28</u>
<u>Total</u> 96
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Answer:
The solution of the system is (6, 9).
Step-by-step explanation:
Solve one of the variables and substitute the answer for the other variable.
Select one of the problems and solve for x.
3x+y=27
Subtract y from both sides.
3x+-y=27
Divide both sides by three.
x=1/3(-y + 27)
Multiply 1/3 by -y + 27.
x = -1/3y + 9
Replace -y/3 + 9 for x in the other problem 3x-2y=0.
3(-1/3y + 9) - 2y = 0
Multiply 3 by -y/3 + 9.
−y+27−2y=0
Add -y to -2y.
−3y+27=0
Subtract 27 from both sides of the problem.
−3y=−27
Divide both sides by −3.
y=9
Replace 9 for y in x=−1/3y+9.
x=−1/3*9+9
Multiply −1/3 times 9.
x=-3+9
Add 9 to -3.
x = 6.
x = 6, y = 9.
The approximate area of the decagon with a side of 8cm comes to be 492.40 cm².
The side of the regular decagon = 8cm
<h3>What is a regular decagon?</h3>
A regular decagon is a polygon with 10 sides that are equal to each other.
The area of a regular decagon with side a is:
So, the area A of the regular decagon with a side of 8cm:
A=492.40 cm²
Therefore, the approximate area of the decagon is 492.40 cm².
To get more about the decagon visit:
brainly.com/question/19899848