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3 years ago

13

What is the percentage difference in average lifetime earnings of a college graduate earning $60,000 / year vs. a high school gr

aduate earning $38,000 / year?

1 answer:

katen-ka-za [31]3 years ago

6 0

Answer: 37

Step-by-step explanation:

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What is the reason for statement 4 in this proof?

Naddika [18.5K]

It's the reflexive property because it's just relating it to itself (def. of reflexive)

As we all know: A=A, B=B, mx=mx, nothing changes.

So the answer is D

5 0

4 years ago

Read 2 more answers

Using the functions f(x) = (3 - x)/(x2 + 4) and g(x) = 3x, find the value of (f*g)(2).

wariber [46]

9514 1404 393

Answer:

(f×g)(2) = 3/4

Step-by-step explanation:

For each of the functions, put 2 where x is and evaluate the expression.

f(2) = (3 -2)/(2² +4) = 1/8

g(2) = 3×2 = 6

Then the product is ...

(f×g)(2) = f(2)×g(2) = (1/8)×6 = 6/8

(f×g)(2) = 3/4

4 0

3 years ago

Determine the value of x for the diagram shown.

TEA [102]

Answer:

C) 60

Step-by-step explanation:

180 - 120

4 0

3 years ago

Read 2 more answers

find the volume of the solid formed by revolving the region bounded by the graphs of y = 4x - x^2 and f(x) = x^2 from [0,2] abou

Neko [114]

Answer:

$v = \frac{32\pi}{3}$

or

$v=33.52$

Step-by-step explanation:

Given

$f(x) = 4x - x^2$

$g(x) = x^2$

$[a,b] = [0,2]$

Required

The volume of the solid formed

Rotating about the x-axis.

Using the washer method to calculate the volume, we have:

$\int dv = \int\limit^b_a \pi(f(x)^2 - g(x)^2) dx$

Integrate

$v = \int\limit^b_a \pi(f(x)^2 - g(x)^2)\ dx$

$v = \pi \int\limit^b_a (f(x)^2 - g(x)^2)\ dx$

Substitute values for a, b, f(x) and g(x)

$v = \pi \int\limit^2_0 ((4x - x^2)^2 - (x^2)^2)\ dx$

Evaluate the exponents

$v = \pi \int\limit^2_0 (16x^2 - 4x^3 - 4x^3 + x^4 - x^4)\ dx$

Simplify like terms

$v = \pi \int\limit^2_0 (16x^2 - 8x^3 )\ dx$

Factor out 8

$v = 8\pi \int\limit^2_0 (2x^2 - x^3 )\ dx$

Integrate

$v = 8\pi [ \frac{2x^{2+1}}{2+1} - \frac{x^{3+1}}{3+1} ]|\limit^2_0$

$v = 8\pi [ \frac{2x^{3}}{3} - \frac{x^{4}}{4} ]|\limit^2_0$

Substitute 2 and 0 for x, respectively

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ \frac{2*0^{3}}{3} - \frac{0^{4}}{4} ])$

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ 0 - 0])$

$v = 8\pi [ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ]$

$v = 8\pi [ \frac{16}{3} - \frac{16}{4} ]$

Take LCM

$v = 8\pi [ \frac{16*4- 16 * 3}{12}]$

$v = 8\pi [ \frac{64- 48}{12}]$

$v = 8\pi * \frac{16}{12}$

Simplify

$v = 8\pi * \frac{4}{3}$

$v = \frac{32\pi}{3}$

or

$v=\frac{32}{3} * \frac{22}{7}$

$v=\frac{32*22}{3*7}$

$v=\frac{704}{21}$

$v=33.52$

8 0

3 years ago

They will build another fence that is 48 feet long. The posts can be a minimum of 5 feet apart and a maximum of 9 feet apart. Th

lozanna [386]

6 posts at 8 feet apart because 8 goes into 48 equally and you get 6. 48/8=6

Hope this helps!

4 0

3 years ago