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Alenkinab [10]
2 years ago
11

Copy the problems onto your paper, mark the given and prove the statements asked. Prove, triangle CAV is congruent to triangle C

EV

Mathematics
1 answer:
lys-0071 [83]2 years ago
7 0

<u>Quadrilateral</u> is a family of <em>plane shapes</em> that have four straight sides. Thus the <u>sum</u> of their <em>internal</em> angles is 360^{o}. Examples include rectangle, square, rhombus, trapezium, and kite.

A kite is a <em>plane shape</em> that has its <u>adjacent </u>sides to have <u>equal</u> measures.

The given <u>diagram</u> in the question is a kite that has its <em>specific properties</em> compared to other<u> quadrilaterals</u>.

Thus, the required <em>proof</em> is stated below:

Given: ΔCAV and ΔCEV

Prove that: ΔCAV ≅ ΔCEV

Then,

CE ≅ CA (<u>length</u> of <em>side</em> property of a <u>kite</u>)

EV ≅ AV (<u>length</u> of <u>side</u> property of a <em>kite</em>)

<ACV ≅ <ECV (<u>bisected</u> property of a given <em>angle</em>)

<AVC ≅ <EVC (<u>bisected</u> property of a given <u>angle</u>)

CV is a common side to ΔCAV and ΔCEV

Therefore it can be <em>deduced</em> that;

ΔCAV ≅ ΔCEV (<em>Angle-Angle-Side</em> <u>congruent</u> theorem)

For more clarifications on the properties of a kite, visit: brainly.com/question/2918354

#SPJ1

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Answer:

a) A student travelling to school on public transport: 15/52 or 0.231

b) A student walking to school: 16/52 or 0.308

c) A student not cycling to school: 43/52 or 0.827

Step-by-step explanation:

Total people = 52

Travel Method          Frequency

Public Transport           12

Car                                 15

Cycle                               9

Walk                                16

Find the relative frequency of.

The formula used will be: Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}

a) A student travelling to school on public transport:

Given Frequency: 12

Size of sample space: 52

Apply formula: Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}

Fraction = 12/52

Decimal = 0.231

b) A student walking to school

Given Frequency: 16

Size of sample space. 52

Apply formula: Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}

Fraction = 16/52

Decimal = 0.308

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We will consider all students except those who cycle.

12+15+16 = 43

Given Frequency: 43

Size of sample space. 52

Apply formula: Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}

Fraction = 43/52

Decimal = 0.827

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