M=153.46w, L=128.90+127.68w they will be equal when M=L so
153.46w=128.90+127.68w subtract 127.68 from both sides...
25.78w=128.90 divide both sides by 25.78
w=5
So after five weeks they have deposited the same amount of money.
Each of them has deposited <span>$153.46*5=$767.30, so the account has twice that amount.
Thus the total amount in the account is 767.30*2=$1534.60</span>
The answer: $6964.42
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Answer:
- <em>1. Morty's total cost for the items he purchased was </em><u><em>$210</em></u>
- <em>2. Morty's revenue from the sale of the items was </em><u><em>$547</em></u>
- <em>3. Morty's Total profit was </em><u><em>$337</em></u>
<em />
Explanation:
The complete question is:
<em>Morty buys and sells computer parts. He bought two monitors for $25 each and later sold them for $88 each. He bought four cases for $15 each and later sold them for $24 each. He bought five memory modules for $20 each and later sold them for $55 each.</em>
<em />
- <em>Morty's total cost for the items he purchased was</em>
- <em>Morty's revenue from the sale of the items was</em>
- <em>Morty's Total profit was </em>
<em />
<h2><em>Solution</em></h2>
<em />
<u><em>1. Morty's total cost for the items he purchased was</em></u>
<em />
Build a table with the number of parts and their costs:
Component Amout Unit cost Total cost
$ $
Monitors 2 25 50
Cases 4 15 60
Memory 5 20 100
Total cost = $50 + $60 + $100 = $210
<u><em>2. Morty's revenue from the sale of the items was</em></u>
<em />
Build a table with the number of parts and their selling prices:
Component Amout Unit price Total cost
$ $
Monitors 2 88 176
Cases 4 24 96
Memory 5 55 275
Total revenue: $176 + $96 + $275 = $547
<u><em>3. Morty's Total profit was </em></u>
<em />
The total profit is the total revenue less the total cost: $547 - $210 = $337.
Answer:
9
Step-by-step explanation:
Answer:
I think your functions are 
,
and 
If yes then then the third function which is .
Step-by-step explanation:
The function 
where c is a constant has
Domain : 
Range : ( 0 , ∞ )
The above range is irrespective of the value of c.
I have attached the graph of each of the function, you can look at it for visualization.
- <em> ⇒ </em>This function is same as so its range is <em>( 0 , ∞ )</em>.
- <em> ⇒ </em>If we double each value of the function
, which has range ( 0 , ∞ ), but still the value of extremes won't change as 0*2=0 and ∞*2=∞. Therefore the range remains as <em>( 0 , ∞ )</em>.
- <em></em> ⇒ If we add 2 to each value of the function , which has range ( 0 , ∞ ), the lower limit will change as 0+2=2 but the upper limit will be same as ∞. Therefore the range will become as <em>( 2 , ∞ )</em>.
