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3 years ago

What is 300 divided by 10

Mathematics

2 answers:

leonid [27]3 years ago

8 0

30. If you have 300 apples and wanted to separate them in piles, with 10 in each pile, you would have 30 piles.

Vera_Pavlovna [14]3 years ago

7 0

300 divided by 10 is 30

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Drag each tile to the correct box

ValentinkaMS [17]

Answer:

Arranging the solutions from the least to the highest;

1. 1.743 x 10⁻²

2. 3.626 x 10⁻²

3. 4.64 x 10⁻²

4. 3.162 x 10²

5. 4.214 x 10³

Step-by-step explanation:

The solutions of the mathematical expression are calculated as follows;

$1. \ \ (4.3\times 10^6)(9.8\times 10^{-4}) = (4.3\times 9.8\times 10^{6-4}) = (42.14\times 10^2)= 4.214 \times 10^3$

$2. \ \ (2.9\times 10^7)(1.6\times 10^{-9}) = (2.9\times 1.6\times 10^{7-9}) = 4.64\times 10^{-2}$

$3. \ \ \frac{(4.7 \times 10^3)(8.6\times 10^{-7})}{(3.8\times 10^{-4})(6.1 \times 10^2)} = \frac{(4.7\times 8.6\times 10^{3-7})}{(3.8\times 6.1\times 10^{-4+2})} = \frac{4.042 \times 10^{-3}}{2.318\times 10^{-1}} = 1.743\times 10^{-2}$

$4. \ \ (4.9\times 10^3)(7.4\times 10^{-6}) = (4.9\times 7.4\times 10^{3-6}) = 3.626\times 10^{-2}$

$5. \ \ \frac{(3.9 \times 10^5)(8.7\times 10^{-3})}{(3.7\times 10^{-5})(2.9 \times 10^8)} = \frac{(3.9\times 8.7\times 10^{5-3})}{(3.7\times 2.9\times 10^{-4 +8 })} = \frac{3.393 \times 10^{-1}}{1.073\times 10^{-3}} = 3.162\times 10^{2}$

Arranging the solutions from the least to the highest;

1. 1.743 x 10⁻²

2. 3.626 x 10⁻²

3. 4.64 x 10⁻²

4. 3.162 x 10²

5. 4.214 x 10³

4 0

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jasenka [17]

Answer:

Step-by-step explanation:

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3 years ago

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Need a little help with this question.

kaheart [24]

Answer:

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Step-by-step explanation:

A ailen maked that thats cazy

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jok3333 [9.3K]

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It's 1/4

Step-by-step explanation:

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3 years ago

Suppose the coefficient matrix of a system of linear equations has a pivot position in every row. Explain why the system is cons

mestny [16]

Answer: A.

The system is consistent because the rightmost column of the augmented matrix is not a pivot column.

Explanation: a system is consistent if and only if the rightmost column of the augmented matrix is not a pivot column. Since every column of the coefficient matrix is a pivot column, none of the leading coefficients are in the rightmost column of the augmented matrix. Therefore the rightmost column of the augmented matrix cannot be a pivot column and the system must be consistent.

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4 years ago