I need help is it A B C or D

astra-53 [7]

#12 1000 because their is 2 ticks to $2000 meaning that each tick is $1000

#13 slope =1/2 (up 1 over 2) y intercept= 1 because it starts at y(0,1)

#14 y=1/2x+1
#15 this slope means that the savings account saves on average $2000 dollars every 2months.

I hope this helps if it did please help me out by marking this comment as the brainiest answer. Helps me out a lot goodluck

8 0

2 years ago

For any triangle, the sum of the measure of the three angles equals 180 degrees. Two of the angles have the same measure,a,and t

vivado [14]

45+2a=180. You should always try to write down an equation for problems like these. Subtract the 45 to both sides of the equal sign. This gets you 2a=135. Divide the 2 on both sides and you get a=67.5 degrees. I hope that i helped, enjoy

8 0

2 years ago

Triangle DNO has vertices at D(5, 8), N(– 3, 10), and O(– 3, 6). If vertex D is translated 4 units to the right, the best name f

prisoha [69]

Using distance between two points to find the lengths of the edges of the triangle, the correct option is:

b. Isosceles

The distance between two points, $(x_1,y_1)$ and $(x_2,y_2)$ , is given by:

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Vertex D is translated 4 units to the right is (9,8).

The lengths of the edges are:

$DN = \sqrt{(9 - (-3))^2 + (8 - 10)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}$

$DO = \sqrt{(9 - (-3))^2 + (8 - 6)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}$

$NO = \sqrt{(-3 - (-3))^2 + (10 - 6)^2} = \sqrt{0^2 + 4^2} = 4$

Two edges of the same length, hence, it is an isosceles triangle, given by option b.

You can learn more about distance between two points at brainly.com/question/18345417

6 0

2 years ago

How does the volume of an oblique cylinder change if the radius is reduced to 2/9 of its original size and the height is quadrup

vesna_86 [32]

Volume of a cylinder = π r² h

Let us assume the following values:
radius = 9
height = 10

Volume = 3.14 * 9² * 10
= 3.14 * 81 *10
Volume = 2,543.40

Changes:
radius is reduced to 2/9 of its original size = 9 x 2/9 = 2
height is quadrupled = 10 x 4 = 40

Volume = π r² h
= 3.14 * 2² * 40
= 3.14 * 4 * 40
Volume = 502.40

Original volume = 2543.40 V.S. Volume after change = 502.40

The volume of an oblique cylinder decreased when its radius was decreased to 2/9 of its original size and its height is increased 4 times.

4 0

3 years ago

Triangle abc is similar to triangle FGH solve for p plebs.

12345 [234]

The value of p is 21

Step-by-step explanation:

ΔABC ~ ΔFGH

$\frac{ab}{fg} = \frac{bc}{gh} \\ \frac{35}{p} = \frac{10}{6} \\ p = \frac{35 \times 6}{10} \\ p = \frac{210}{10} \\ p = 21 \\ \\ or \\ \\ \frac{ab}{fg} = \frac{ac}{fh} \\ \frac{35}{p} = \frac{30}{18} \\ p = \frac{35 \times 18}{30} \\ p = \frac{630}{30} \\ p = 21$

So, the value of p is 21

Hope it helpful and useful :)

5 0

3 years ago