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just olya [345]

2 years ago

7

Given AQRS-AXYZ, what is the value of tan(Q)? A) 3/5 B) 3/4 C) 4/5 D) 4/3

1 answer:

iren [92.7K]2 years ago

3 0

The answer is B.

Since ΔQRS ~ ΔXYZ, the value of tan(Q) is :

∠Q = ∠X
tan(Q) = tan(X)
tan(X) = 3/4
tan(Q) = 3/4

You might be interested in

Rewrite the expression $6j^2 - 4j 12$ in the form $c(j p)^2 q$, where $c$, $p$, and $q$ are constants. What is $\frac{q}{p}$

solniwko [45]

$Rewrite the expression 6j^2 - 4j + 12$ in the form $c(j + p)^2 + q$, where $c$, $p$, and $q$ are constants. What is $\frac{q}{p}$$

The ratio of $\frac{q}{p}$ = - 34

How to solve such questions?

Such Questions can be easily solved just by some Algebraic manipulations and simplifications. We just try to make our expression in the form which question asks us. This is the best method to solve such questions as it will definitely lead us to correct answers. One such method is completing the square method.

Completing the square is a method that is used for converting a quadratic expression of the form $ax^{2} + bx + c$ to the vertex form

$a(x - h)^{2} + k$ . The most common application of completing the square is in solving a quadratic equation. This can be done by rearranging the expression obtained after completing the square: $a(x + m)^{2} + n$ , such that the left side is a perfect square trinomial

$6j^2 - 4j +12$

= $6(j^2 - \frac{2}{3} j )+12$

= $$6(j^2 - \frac{2}{3} j + \frac{1}{9} )+\frac{102}{9}$ (Completing Square method)

= $6( j- \frac{1}{3} )^{2} + \frac{34}{3}$

On comparing with the given equation we get

p = - $\frac{1}{3}$ and q = $\frac{34}{3}$

∴ $\frac{q}{p}$ = $\frac{\frac{34}{3} }{\frac{-1}{3} }$

= - 34

Learn more about completing the square method here :

brainly.com/question/26107616

#SPJ4

7 0

2 years ago

In your garden, sandy soil can be corrected by adding what?

Alex17521 [72]

Maybe by adding water

4 0

2 years ago

solmaris [256]

Answer:

The initial mass of the sample was 16 mg.

The mass after 5 weeks will be about 0.0372 mg.

Step-by-step explanation:

We can write an exponential function to model the situation.

Let the initial amount be A. The standard exponential function is given by:

$P(t)=A(r)^t$

Where r is the rate of growth/decay.

Since the half-life of Palladium-100 is four days, r = 1/2. We will also substitute t/4 for t to to represent one cycle every four days. Therefore:

$\displaystyle P(t)=A\Big(\frac{1}{2}\Big)^{t/4}$

After 12 days, a sample of Palladium-100 has been reduced to a mass of two milligrams.

Therefore, when x = 12, P(x) = 2. By substitution:

$\displaystyle 2=A\Big(\frac{1}{2}\Big)^{12/4}$

Solve for A. Simplify:

$\displaystyle 2=A\Big(\frac{1}{2}\Big)^3$

Simplify:

$\displaystyle 2=A\Big(\frac{1}{8}\Big)$

Thus, the initial mass of the sample was:

$A=16\text{ mg}$

5 weeks is equivalent to 35 days. Therefore, we can find P(35):

$\displaystyle P(35)=16\Big(\frac{1}{2}\Big)^{35/4}\approx0.0372\text{ mg}$

About 0.0372 mg will be left of the original 16 mg sample after 5 weeks.

5 0

3 years ago

Plz tell me this solution it's very urgent

a_sh-v [17]

Step-by-step explanation:

here is fig 15

x=36 (v.o.a are equal)

36+y=180

y=180-36=144

y=z=144 vertically

3 0

3 years ago

What is 4.16 repeating as a fraction

strojnjashka [21]

4.16=416/100
416/100=4•104/4•25
=104/25
4.16=104/25

8 0

3 years ago

Read 2 more answers