Answer:
Step-by-step explanation:
a). Stock price arranged as arithmetic sequence will be,
5, 8, 11, 14
b). Since, explicit formula of an arithmetic sequence is given by,

Here,
= nth term of the sequence
a = first term
n = number of term
d = common difference
From the table attached,
First term of the sequence 'a' = 5
Common difference 'd' = 8 - 5 = 3
Therefore, explicit formula for the given sequence will be,


c). Slope intercept form of the equation will be,
y = 3x + 2
d). Input out values for the graph of the given equation,
x 0 1 2 3
y 2 5 8 11
By using this data we can graph the line.
In general if multiplying, move decimal to RIGHT by whatever the exponent is.
In this example 10^1, the exponent = 1
9.4 with decimal moved 1 place to right = 94
Answer:
y - 7 = 16/13(x - 7)
General Formulas and Concepts:
<u>Alg I</u>
Point-Slope Form: y - y₁ = m(x - x₁)
Slope Formula: 
Step-by-step explanation:
<u>Step 1: Define</u>
Point (-6, -9)
Point (7, 7)
<u>Step 2: Find slope </u><u><em>m</em></u>
- Substitute:

- Add:

<u>Step 3: Write equation</u>
y - 7 = 16/13(x - 7)
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:

where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:

Hence, the half life of the sample of phosphorus-32 is 
<span>the answer to 1.47 divided by 3.5 is 0.42. When you use different power of 10 to multiply the dividend and the divisor, the answer changes to different multiples of 0.42 in terms of 10. The answer could be 0.042 or 4.2 etc depending on the power of 10 used to multiply the dividend and divisor.</span>