Given: Different equations
To Determine: Which would be best solved using difference of two squares
Solution
The factorization of a difference of two squares is given below
Let us examine each of the given equation
From the above,
The two equation above can be solved by difference of two square, but the equation below is the easiest solved using differnce of two square
x² - 25 = 0
Answer:
9:59
Step-by-step explanation:
Answer:
Area of rectangle possible. : 6ft² ; 10 ft², 12 ft²
Step-by-step explanation:
Feets of fencing = 14
Perimeter = 14
Let x = Length y = width
Perimeter = 2(x + y)
For x = 1
2(1 + y) = 14
1 + y = 7
y =6
Area of rectangle ; x *y = 1 * 6 = 6 ft²
For x = 2
2(2 + y) = 14
2 + y = 7
y = 5
Area of rectangle ; x *y = 2 * 5 = 10 ft²
For x = 3
2(3 + y) = 14
3 + y = 7
y =4
Area of rectangle ; x *y = 3 * 4 = 12 ft²
For x = 4
2(1 + y) = 14
4 + y = 7
y = 3
Area of rectangle ; x *y = 4 * 3 =12 ft²
Hence, Area of rectangle possible. : 6ft² ; 10 ft², 12 ft²
I hope this helps you
A=Area
b=base
h=height
A=b×h/2
A=1/2.b+1/2.h
It is (2/3d)^3
Make sure the exponent is on the outside. This is because you are raising 2/3d. Not just D
