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SashulF [63]
1 year ago
9

Drag the tiles to the correct boxes to complete the pairs Match each inequality to the number line that represents its solution



Mathematics
1 answer:
Anna [14]1 year ago
5 0

Answer:

x ≤ 7 => - \frac{13x}{18} + \frac{5}{9}  \geq  - \frac{9}{2}

x ≤ 8 => -\frac{x}{10} + \frac{1}{5} ≥ -\frac{33}{55}

x ≤ -5 => - \frac{50x}{3} - \frac{11}{6} \geq \frac{163}{2}

x ≤ -6 => \frac{3x}{2} + 105 ≤ 96

Step-by-step explanation:

-\frac{x}{10} + \frac{1}{5} ≥ -\frac{33}{55}

\frac{1}{5} + \frac{33}{55} ≥ \frac{x}{10} / *10

2 + 6 ≥ x

8 ≥ x

- \frac{50x}{3} - \frac{11}{6} \geq \frac{163}{2}  / *6

- 100x - 11 ≥ 489

-500 ≥ 100x

-5 ≥ x

\frac{3x}{2} + 105 ≤ 96

\frac{3x}{2} ≤ 96 - 105  / * \frac{2}{3}

x ≤ -6

- \frac{13x}{18} + \frac{5}{9}  \geq  - \frac{9}{2}  /*18

-13x + 10 ≥ - 81

-13x ≥ -91 /:-13

x ≥ 7

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Answer:

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Step-by-step explanation:

we know that

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Remember that

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In this problem we have

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A car is on a driveway that is inclined 10 degrees to the horizontal. A force of 490 lb is required to keep the car from rolling
lara31 [8.8K]

Answer:

a) weight  of the car = 2816,1 lbs

b) 2773 lbs

Step-by-step explanation:

The equilibrium force is 490 lbs. That force keep the car at rest, then

∑ Fy  =  0     and  ∑Fx  =  0

Forces acting on the car:

The external force   490 lbs

weight of the car   uknown

Normal force

sin∠10°  =  0,174

cos∠10° = 0.985

∑Fx  =  0         mg*sin10°- 490 = 0      ∑Fy =  0      mg*cos10° - N  =  0

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N = 2773 lbs

Then equal force in magnitude and in opposite direction will car exets on the driveway

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3 years ago
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