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rewona [7]
2 years ago
5

Urgently needed see image

Mathematics
1 answer:
Lorico [155]2 years ago
7 0

y2-y1 =M(x2-x1)

Ok Sir, you gave points : (2,1) and (3,4)

4-1/3-2 = 3

Ok we know our slope is 3, now pick any of the two points, and make an equation for this line, so lets go ahead and pick #1, (2,1)

Formula is same as before

y-1=3x-6

y=3x-5

I think its correct, pick as brainless sir, thanks.

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PLEASE HELP!! DUE SOON!!
mr Goodwill [35]

Answer:

w

Step-by-step explanation:

7 0
2 years ago
Help me y’all! Need to turn this in tonight
melomori [17]
Answer: y = -1

Explanation: the y axis is the vertical line, the crossing line intersects at -1.

Hope this helps!
8 0
2 years ago
12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5
Gnesinka [82]

\large\underline{\sf{Solution-}}

Given that,

In <u>triangle TPQ, </u>

  • RS || PQ,

  • RS = 3 cm,

  • PQ = 6 cm,

  • ar(∆ TRS) = 15 sq. cm

As it is given that, <u>RS || PQ</u>

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

\rm\implies \: \triangle TPQ \:  \sim \: \triangle TRS \:  \:  \:  \:  \:  \:  \{AA \}

<u>Now, We know </u>

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)}  = \dfrac{ {PQ}^{2} }{ {RS}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{ {6}^{2} }{ {3}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{36 }{9}

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = 4

\rm\implies \:ar( \triangle \: TPQ)  = 60 \:  {cm}^{2}

3 0
2 years ago
SOMEONE PLEASE JUST ANSWER THIS FOR BRAINLIEST!!!
Sloan [31]

ANSWER

P-G = 11{w}^{4} - 5 {w}^{2}  {z}^{2}   - 4z^{4}

EXPLANATION

The given polynomials are:

G =  - 3 {w}^{4}  + 2 {w}^{2}  {z}^{2}  + 5z^{4}

and

P = 8 {w}^{4}   - 3{w}^{2}  {z}^{2}  + z^{4}

We want to subtract these two polynomials.

P-G = 8 {w}^{4}   - 3{w}^{2}  {z}^{2}  + z^{4}  - (- 3 {w}^{4}  + 2 {w}^{2}  {z}^{2}  + 5z^{4} )

Expand the right hand side to obtain:

P-G = 8 {w}^{4}   - 3{w}^{2}  {z}^{2}  + z^{4}   + 3 {w}^{4}   -  2 {w}^{2}  {z}^{2}   -  5z^{4}

Group the similar terms:

P-G = 8 {w}^{4}  + 3 {w}^{4}- 3{w}^{2}  {z}^{2} -  2 {w}^{2}  {z}^{2}   -  5z^{4} + z^{4}

Combine the similar terms to get:

P-G = 11{w}^{4} - 5 {w}^{2}  {z}^{2}   - 4z^{4}

7 0
3 years ago
Si sumamos el cuadrado de un número más el cuadruple del siguiente resulta 225 ¿De que número se trata?
Talja [164]

Answer:

What does it say in english

Step-by-step explanation:

ill answer it in comments if you tell me what it says in english

5 0
3 years ago
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