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Leno4ka [110]
2 years ago
9

Determine whether the triangles can be proved similar. If they are similar, write a similarity statement. If they are not simila

r, explain why.

Mathematics
1 answer:
HACTEHA [7]2 years ago
5 0

Answer: No, they are not similar

Step-by-step explanation:

       Similar triangles are triangles with congruent angles.

                   33° ≠ 32°

       These triangles are not similar.

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Explain your answer !! <br> Have a nice day <br><br> Will give braisnlt
Fudgin [204]
I NEED POINT ILYSM AND I HOPE U HAVE A WONDERFUL DAY AND U ARE LOVED AND ILYSM MWA
4 0
2 years ago
A piece of copper tubing is in the shape of a hexagonal prism. The area of the base of the prism is 3 square centimeters. The vo
Evgen [1.6K]

Answer: 17 cm

Step-by-step explanation:

For a regular figure where the area of the base is B, and the height is H, the volume is calculated as:

V = B*H

Here we know that the base of the prism is B = 3 cm^2, and the volume of the prism is 51 cm^3

Then:

B = 3cm^2

V = 51cm^3

If we replace those in the equation above, we get:

51 cm^3 = (3cm^2)*H

Solving this for H gives:

(51 cm^3)/(3 cm^2) = H = 17 cm

The height of the tubing is 17 cm

7 0
3 years ago
if a square + b square + c square minus ab minus bc minus ca equals to zero, prove that A equals to B equal to C
lawyer [7]
A^2 + b^2 + c^2  - ab - bc - ca = 0
a.a + b.b + c.c = a.b + b.c + c.a

equating  term by term:- 
a = b
b = c 
c = a

Therefore a = b = c 
8 0
3 years ago
7x^2=9+x what are the values of x<br><br>Will give medal and points
DENIUS [597]
7x² = 9 + x   Subtract x from both sides
7x² - x = 9    Subtract 9 from both sides
7x² - x - 9 = 0   Use the Quadratic Formula

a = 7 , b = -1 , c = -9

x = \frac{-b \pm  \sqrt{b^2 - 4ac} }{2a}   Plug in the a, b, and c values
x = \frac{- (-1) \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Cancel out the double negative
x = \frac{1 \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Square -1
x = \frac{1 \pm  \sqrt{1 - 4(7)(-9)} }{2(7)}   Multiply 7 and -9
x = \frac{1 \pm  \sqrt{1 - 4(-63} }{2(7)}   Multiply -4 and -63
x = \frac{1 \pm  \sqrt{1 + 252} }{2(7)}   Multiply 2 and 7
x = \frac{1 \pm  \sqrt{1 + 252} }{14}   Add 1 and 252
x = \frac{1 \pm  \sqrt{253} }{14}   Split up the \pm
x = \left \{ {{ \frac{1 +  \sqrt{253} }{14} } \atop { \frac{1 -  \sqrt{253} }{14} }} \right.
The approximate square root of 253 is <span>15.905973.
</span>x ≈ \left \{ { \frac{1 + 15.905973}{14} } \atop { \frac{1 - 15.905973}{14} }} \right   Add and subtract
x ≈ \left \{ {{ \frac{16.905973}{14} } \atop { \frac{14.905973}{14} }} \right.   Divide
x ≈ \left \{ {{1.2075} \atop {1.0647}} \right.   Round to the nearest hundredth
x ≈ \left \{ {{1.21} \atop {1.06}} \right.

<span>
</span>
7 0
3 years ago
Consider the graph of the linear equation 2x - 5y = 10.
jeyben [28]

Answer:

x-intercept= (5,0)

y-intercept= (0,-2)

Slope= 2/5

Step-by-step explanation:

7 0
3 years ago
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