All categories

2 years ago

Help me out please thanks

Mathematics

2 answers:

Soloha48 [4]2 years ago

4 0

Answer: Choice D is correct. The slope is 1.5

This means that for every hour, the temperature is increasing by 1.5 degrees Fahrenheit.

=======================================================

Work Shown:

slope = rise/run

slope = (change in y)/(change in x)

slope = (change in temperature)/(change in time)

slope = 6/4 .... see note below

slope = 3/2

slope = 1.5

note: The 6 refers to the jump from -2 to 4; the denominator 4 represents the amount of elapsed time from 8 AM to 12 PM

SVEN [57.7K]2 years ago

3 0

Answer:

1.5 is the correct answer

Step-by-step explanation:

The time it four hours. In those 4 hours the temperature changer by 6 degrees. So 6 divided by 4 is 1.5.

You might be interested in

Covert the fowllowing fractions to a decimal 2/5

Talja [164]

The answer will be 0.40 because 2 divided by 5 is 0.40

8 0

2 years ago

Read 2 more answers

What is 228/298 simplified to its lowest term?

rosijanka [135]

Find the GCF of 228 and 298 and that would be 2.

divide both the numerator and denominator by 2

simplify

Answer: 114/149.

5 0

3 years ago

What is 1+1=?.......................

Stella [2.4K]

Answer:

Step-by-step explanation:

$1 + 1 = 2$

thank you

3 0

2 years ago

Read 2 more answers

The expression (secx + tanx)2 is the same as _____.

trapecia [35]

Answer:

The expression $\bold{(\sec x+\tan x)^{2} \text { is same as } \frac{1+\sin x}{1-\sin x}}$

Solution:

From question, given that $\bold{(\sec x+\tan x)^{2}}$

By using the trigonometric identity $(a + b)^{2} = a^{2} + 2ab + b^{2}$ the above equation becomes,

$(\sec x+\tan x)^{2} = \sec ^{2} x+2 \sec x \tan x+\tan ^{2} x$

We know that $\sec x=\frac{1}{\cos x} ; \tan x=\frac{\sin x}{\cos x}$

$(\sec x+\tan x)^{2}=\frac{1}{\cos ^{2} x}+2 \frac{1}{\cos x} \frac{\sin x}{\cos x}+\frac{\sin ^{2} x}{\cos ^{2} x}$

$=\frac{1}{\cos ^{2} x}+\frac{2 \sin x}{\cos ^{2} x}+\frac{\sin ^{2} x}{\cos ^{2} x}$

On simplication we get

$=\frac{1+2 \sin x+\sin ^{2} x}{\cos ^{2} x}$

By using the trigonometric identity $\cos ^{2} x=1-\sin ^{2} x$ ,the above equation becomes

$=\frac{1+2 \sin x+\sin ^{2} x}{1-\sin ^{2} x}$

By using the trigonometric identity $(a+b)^{2}=a^{2}+2ab+b^{2}$

we get $1+2 \sin x+\sin ^{2} x=(1+\sin x)^{2}$

$=\frac{(1+\sin x)^{2}}{1-\sin ^{2} x}$

$=\frac{(1+\sin x)(1+\sin x)}{1-\sin ^{2} x}$

By using the trigonometric identity $a^{2}-b^{2}=(a+b)(a-b)$ we get $1-\sin ^{2} x=(1+\sin x)(1-\sin x)$

$=\frac{(1+\sin x)(1+\sin x)}{(1+\sin x)(1-\sin x)}$

$= \frac{1+\sin x}{1-\sin x}$

Hence the expression $\bold{(\sec x+\tan x)^{2} \text { is same as } \frac{1+\sin x}{1-\sin x}}$

8 0

2 years ago

Answer the questions about the following polynomial.

GalinKa [24]

Answer:

Given:

6x^2+ 1/8

The constant is term is:

1/8, the term with no variable

The leading term is:

6x^2, the term with that included a variable of the greatest degree

The leading coefficient is:

6, the coefficient of the leading term

4 0

2 years ago

Read 2 more answers