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3 years ago

How do I put 6.7, 2 pi, 55/9, 6 in least to greatest

Mathematics

2 answers:

Setler [38]3 years ago

4 0

Sdfghfdsxcvbhwertyu34567898765432345

zheka24 [161]3 years ago

4 0

Answer:

answer is 1/6 on edg

Step-by-step explanation:

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Given the original number n. Multiply the number by 9. Add 99. Divide this sum by 9. Subtract the original number, n, from the q

tangare [24]

Answer:

Step-by-step explanation:

Hello,

Given the original number n.

$\large \boxed{n}$

Multiply the number by 9.

$\large \boxed{9n}$

Add 99.

$\large \boxed{9n+99}$

Divide this sum by 9.

$\large \boxed{\dfrac{9n+99}{9}=n+11}$

Subtract the original number, n, from the quotient.

$\large \boxed{n+11-n=11}$

Thank you.

4 0

2 years ago

Find the inverse of the given matrix, if it exists.Aequals=left bracket Start 3 By 3 Matrix 1st Row 1st Column 1 2nd Column 0 3

BabaBlast [244]

Answer:

$A^{-1}=\left[ \begin{array}{ccc} \frac{1}{9} & \frac{4}{27} & - \frac{2}{27} \\\\ \frac{8}{9} & \frac{5}{27} & \frac{11}{27} \\\\ - \frac{4}{9} & \frac{2}{27} & - \frac{1}{27} \end{array} \right]$

Step-by-step explanation:

We want to find the inverse of $A=\left[ \begin{array}{ccc} 1 & 0 & -2 \\\\ 4 & 1 & 3 \\\\ -4 & 2 & 3 \end{array} \right]$

To find the inverse matrix, augment it with the identity matrix and perform row operations trying to make the identity matrix to the left. Then to the right will be inverse matrix.

So, augment the matrix with identity matrix:

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 4&1&3&0&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Subtract row 1 multiplied by 4 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Add row 1 multiplied by 4 to row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&2&-5&4&0&1\end{array}\right]$

Subtract row 2 multiplied by 2 from row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&-27&12&-2&1\end{array}\right]$

Divide row 3 by −27

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Add row 3 multiplied by 2 to row 1

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Subtract row 3 multiplied by 11 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&0&\frac{8}{9}&\frac{5}{27}&\frac{11}{27} \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

As can be seen, we have obtained the identity matrix to the left. So, we are done.

6 0

2 years ago

Question<br> Use the distributive property to multiply the polynomials.<br> -5x2(6x - 1)

nignag [31]

Answer:

-60x + 10

Step-by-step explanation:

-5 x 2(6x - 1)

-10 (6x - 1)

-60x + 10

7 0

2 years ago

Read 2 more answers

12. Ms. Lacy wants to work out. Drop It Like It's Hot gym charges a monthly rate of $25 and

arsen [322]

Answer:

more than 12 classes

Step-by-step explanation:

8 0

2 years ago

Find the volume of a pyramid with a square base, where the perimeter of the base is 16.9\text{ cm}16.9 cm and the height of the

worty [1.4K]

Answer:

Volume of square based pyramid = 116.62 cm³

Step-by-step explanation:

Given:

Perimeter of square base = 16.9 cm

Height of pyramid = 19.6 cm

Find:

Volume of square based pyramid

Computation:

Perimeter of square base = 16.9 cm

4[Side] = 16.9

Side = 4.225 cm

Area of square = Side x Side

Area of square = 4.225 x 4.225

Area of square = 17.85 cm²

Volume of square based pyramid = [Area of square][Height of pyramid] / 3

Volume of square based pyramid = [17.85][19.6] / 3

Volume of square based pyramid = 349.86 /3

Volume of square based pyramid = 116.62 cm³

7 0

2 years ago