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4 years ago

How do I put 6.7, 2 pi, 55/9, 6 in least to greatest

Mathematics

2 answers:

Setler [38]4 years ago

4 0

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zheka24 [161]4 years ago

4 0

Answer:

answer is 1/6 on edg

Step-by-step explanation:

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Solve for y<br> X+y=6 <br> X=4<br> Simplify your answer as much as possible<br> Will give Brainliest

maw [93]

Answer and workin your attached below. Hope it helps

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3 years ago

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I will give branlyest

Anon25 [30]

Answer:

15 3 over 100

$2 \frac{1}{2} + 4 \frac{1}{4} + 9 \frac{1}{4} = 15 \frac{3}{10}$

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3 years ago

Which phrase best describes f(x), graphed on the coordinate plane below? On a coordinate plane, a curve goes through two cycles.

igomit [66]

Answer:

5.6

Step-by-step explanation:

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3 years ago

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If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe

Natalka [10]

Answer:

They encircle the planet $3.76\times 10^{11}$ times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is $6.022\times 10^{23}$

Thus, the number of dust particles is:

$2.5\times 6.022\times 10^{23}=15.055\times 10^{23}$

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: $10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m$

If we line up the particles the distance they could cover is:

$15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}$

Circumference in meters:

$40,076km\times \frac{1000m}{1km}=40,076,000 m$

Therefore,

$\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}$

Hence, they encircle the planet $3.76\times 10^{11}$ times.

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3 years ago

What is the median of this list of numbers? 6, 2, 7, 2, 3

Vika [28.1K]

The median means the number that is in the middle of the spnumber sequence in least to greatest. 1) number the numbers up. 2,2,3,6,7 2) start by crossing off the last from the greatest. Then you can see that 3 is the median.

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3 years ago

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