Answer:
a) Percentage of students scored below 300 is 1.79%.
b) Score puts someone in the 90th percentile is 638.
Step-by-step explanation:
Given : Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.
(a) If the average test score is 510 with a standard deviation of 100 points.
To find : What percentage of students scored below 300 ?
Solution :
Mean 
,
Standard deviation 
Sample mean 
Percentage of students scored below 300 is given by,
Percentage of students scored below 300 is 1.79%.
(b) What score puts someone in the 90th percentile?
90th percentile is such that,
Now, 
Score puts someone in the 90th percentile is 638.
Answer:
7.75
Step-by-step explanation:
You group like terms from the inequality above ie by making the x value stands alone and you can only do this by sending 14 to the left side of the inequality and 4x to the right side. This becomes 45-14 < 4x and that gives you 31 < 4x. Then you divide both side by the number attached to the variable 'x' ie 4. So 31/4 < 4x/4 making x > 31/4 which is 7.75
They’re complimentary angles (add up to 90)
The answer should be X>4
Rearrange the equation by subtracting what is to the right of the greater than sign from both sides of the inequality :
2*x+8-(5*x-4)<0
Step by step solution :
Step 1 :
Pulling out like terms :
1.1 Pull out like factors :
-3x + 12 = -3 • (x - 4)
Equation at the end of step 1 :
Step 2 :
2.1 Divide both sides by -3
Remember to flip the inequality sign:
Solve Basic Inequality :
2.2 Add 4 to both sides
x > 4
