Answer:
x = 1
y = 5
Step-by-step explanation:
You can use either substitution or elimination for this problem. I will use substitution.
Step 1: Replace x in the 1st equation
-10(y-4) + 3y = 5
-10y + 40 + 3y = 5
-7y = -35
y = 5
Step 2: Plug <em>y </em>into an original equation to find <em>x</em>
x = 5 - 4
x = 1
And you have your final answers!
Answer:
by multiplying any non-zero scalar number except 1 to given vector
Step-by-step explanation:
Scalar multiple of one vector is parallel to the vector.
So in given case, v1= (-3,2) and a vector, v2 parallel to it can be find by multiplying any non-zero scalar number except 1 to v1
i.e
v2= n*v1
n is any scalar non-zero number except 1
let n=2 (one of many possible options)
v2= 2*(-3,2)
=(-6,4) !
The best to do this is like this:
5 hundred thousand would be 500,000
12 of 10,000 (should be 12,000)
1,000 tens is 10,000 plus 15 tens is 150 so this is 10,150
7 ones
522,157
Answer: S(t(6)) is equivalent
Step-by-step explanation:
I.e,
S(t(6))
=SXtx6
=(st)(6)
