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yawa3891 [41]
3 years ago
14

It is a customer appreciation week at the vans shoe outlet, Which means all customers are given a 20% discount on all items. A c

ustomer comes in with an birthday coupon for an additional 10% off any shoe item, once the first discount has been applied. The customer buys 3 pairs of shoes for $120.00 each. After the two discounts how much does the customer pay?
Mathematics
1 answer:
SashulF [63]3 years ago
6 0

Answer:

$278.40

Step-by-step explanation:

Note: "...an additional 10% off any shoe item, once the first discount has been applied." (emphasis added).

Note that the customer is buying 3 pairs of shoes for $120 each: 120 x 3 = $360

The first discount is the 20% discount  (on every single item), the second discount is the 10% discount coupon of of any item (which signifies one item only).

Solve for the first discount:

$360 x 0.20 = $72

$360 - 72 = $288.

Next, divide $288 by 3 (to get the individual prices of the shoes:

$288/3 = $96.

The customer then uses a birthday coupon for one of the shoes, which gives an additional 10% off.

$96 x 0.10 = 9.6

$96 - 9.6 = $86.4

Remember, the other two shoes still cost $96 each. Add the price together:

$96 + $96 + $86.4 = $278.40

$278.40 will be the total.

~

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You people in the Algebra 1 course for high school, Are you guys ready for the exams next week? I'm definitely not. Anyway, A ba
Anvisha [2.4K]

Answer:

I think that it D

Step-by-step explanation:

C= .07=70%. So I know that it is not C

A= 30% but the question doesn't even have a 3 in it, so therefore it cannot be A.

B= Is basically the same concept as A. There is no .3 or 3 peroid.

So I say D

4 0
2 years ago
Suppose that the distribution of typing speed in words per minute (wpm) for experienced typists using a new type of split keyboa
KengaRu [80]

Answer:

a. <u>0.5 or 50%</u>

b. <u>0.496 or 49.6%</u>

c. <u>0.8185 or 81.85%</u>

d. <u>Yes, it would be just 0.0013 or 0.13% of probability to find a typist whose speed exceeds 105 wpm</u>

e. <u>0.0252 or 2.52%</u>

f. <u>The qualifying speed would be 47.4 wpm.</u>

Step-by-step explanation:

a. Let's find the z-score this way:

μ  = 60 σ= 15

z-score = (x - μ)/σ

z-score = (60 - 60)/15

z-score = 0

Now, let's calculate the p value for z-score = 0, using the z-table:

<u>p (z=0) = 0.5 or 50%</u>

b. z-score = (x - μ)/σ

z-score = (59.9 - 60)/15

z-score = -0.01

Now, let's calculate the p value for z-score = -.0.01, using the z-table:

<u>p (z = -0.01) = 0.496 or 49.6%</u>

If the question were less or equal than 60, a and b would have the same answer. But in this case, the question is "less than 60 wpm".

c.

z-score = (x - μ)/σ

z-score = (45 - 60)/15

z-score = - 1

Now, let's calculate the p value for z-score = -1, using the z-table:

p (z = -1) = 0.1587

z-score = (x - μ)/σ

z-score = (90 - 60)/15

z-score = 2

Now, let's calculate the p value for z-score = 2, using the z-table:

p (z = 2) = 0.9772

<u>In consequence,</u>

<u>p (-1 ≤ z ≤ 2) = 0.9772 - 0.1587 = 0.8185 or 81.85%</u>

d. z-score = (x - μ)/σ

z-score = (105 - 60)/15

z-score = 3

Now, let's calculate the p value for z-score = 3, using the z-table:

p (z = 3) = 0.9987

In consequence,

p (z > 3) = 1 - 0.9987 = 0.0013

<u>Yes, it would be just a 0.13% of probability to find a typist whose speed exceeds 105 wpm.</u>

e. z-score = (x - μ)/σ

z-score = (75 - 60)/15

z-score = 1

Now, let's calculate the p value for z-score = 1, using the z-table:

p (z = 1) = 0.8413

In consequence,

p (z > 1) = 1 - 0.8413 = 0.1587

and if the two typists are independently selected, then

p = 0.1587 * 0.1587

<u>p = 0.0252 or 2.52%</u>

f. p = 0.2, using the z-table, the z-score is -0.84, then:

z-score = (x - μ)/σ

-0.84 = (x - 60)/15

-12.6 = x - 60

-x = -60 + 12.6

-x = - 47.4

x = 47.4

<u>The qualifying speed would be 47.4 wpm.</u>

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Answer:

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x+8=-6

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x+8-8=-6-8

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Use x=-14 into both of the equations

4(-14+2)=3(-14-2)

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Answer is -14- D)

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Volgvan

Answer:

sin(90\°)=-sin(-90\°)

Step-by-step explanation:

we know that

sin(90\°)=1

sin(-90\°)=-1

therefore

sin(90\°)=-sin(-90\°)

4 0
3 years ago
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