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sergiy2304 [10]
2 years ago
9

Am what I’m writing is correct? I put 2+-2=0

Mathematics
2 answers:
Travka [436]2 years ago
4 0

Answer:

Step-by-step explanation:

Start on point 2

Ends on point -2

Then:

2 + a = -2

a = -2 - 2

a = -4

then the equation is:

2 + (-4) = 0

2 - 4 = 0

atroni [7]2 years ago
3 0

The diagram ends at -2

The equation would be 2-4 = -2

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ololo11 [35]
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3 years ago
A rectangle has length represented as (R +5) and width represented as (R + 2).
svetlana [45]

Answer:

4(R + 5 + R + 2) [Option B]

Step-by-step explanation:

<u>GIVEN :-</u>

  • Length = R + 5
  • Width = R + 2

<u>TO FIND :-</u>

  • Perimeter of the rectangle

<u>FORMULAE TO BE USED :-</u>

For a rectangle with length 'l' and width 'w' , its perimeter = 4(l + w)

<u>SOLUTION :-</u>

Perimeter = 4(R + 5 + R+2)

                 = 4(2R + 7)

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7 0
2 years ago
<img src="https://tex.z-dn.net/?f=%28%20%5Csin%5E%7B2%7D%20%28%20%5Cfrac%7B%5Cpi%7D%7B%204%20%7D%20%20-%20%20%5Calpha%20%29%20%2
guapka [62]

Step-by-step explanation:

\sin^2 (\frac{\pi}{4} - \alpha) = \frac{1}{2}(1 - \sin 2\alpha)

Use the identity

\sin^2 \theta = \dfrac{1 - \cos 2\theta}{2}

on the left side.

\dfrac{1 - \cos [2(\frac{\pi}{4} - \alpha)]}{2} = \frac{1}{2}(1 - \sin 2\alpha)

\dfrac{1 - \cos (\frac{\pi}{2} - 2\alpha)}{2} = \frac{1}{2}(1 - \sin 2\alpha)

Now use the identity

\sin \theta = \cos(\frac{\pi}{2} - \theta)

on the left side.

\dfrac{1 - \sin 2\alpha}{2} = \frac{1}{2}(1 - \sin 2\alpha)

\frac{1}{2}(1 - \sin 2\alpha) = \frac{1}{2}(1 - \sin 2\alpha)

4 0
3 years ago
Find the slope of the line that contains (−3,5) and (3,−9).
Ratling [72]

Answer:

-7/3

Step-by-step explanation:

You would use the slope formula which is (y_2-y_1)/(x_2-x_1).

8 0
3 years ago
Read 2 more answers
Are 12d +36 and 12(d+3) equivalent
Nina [5.8K]

Answer:

Yes

Step-by-step explanation:

They are equivalent as 12d + 36 is the expanded form of 12(d + 3)

4 0
2 years ago
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