Answer:
A) P(Type I error) = 0.045
B) P(Type II) error = 0.1
Step-by-step explanation:
We are told that the reliability of the test is 90% reliable.
Also, we are told that the probability that the test erroneously detects a lie even when the individual is actually telling the truth is 0.045.
Thus;
A) To calculate the probability of type I error:
From statistics, in this question we can say that the probability of a type I error is the probability that the test will erroneously detect a lie even though the individual is actually telling the truth. Thus;
Probability of (type I error) = P(rejecting true null) = 0.045
B) For probability of type II error, it is defined as the error where we accept a null hypothesis that is false. We can say that it produces a false negative and the formula is;
P(Type II) error = 1 - reliability
Reliability in the question is 0.90
Thus;
P(Type II) error = 1 - 0.9
P(Type II) error = 0.1
Answer:
So, to answer this problem, we first have to get rid of the cider cost.
$20-$3.50=$16.50
Since we have $16.50 left, now we have to see how much cotton candy grapes Michaela can buy.
1 pound- $3.75
2 pound- $7.50
3 pound- $11.25
4 pound- $15
5 pound- $18.75
When Michaela buys 5 pounds of grapes, she gets a cost of $18.75.
Since $18.75 is $2.25 more than $16.50, the only option she can choose is 4 pounds.
When Michaela buys 4 pounds, she will spend $15 and she will still have $1.50 left. (If there is no tax.)
In summary, Micheala can buy 4 pounds of grapes without spending more than the rest of the money after buying cider.
(By the way, I LOVE cotton candy grapes.)
Hope this helps!
:)
She has 300 - 15 = 285 dollars left.
285/300 = 95/100 = 95%
The expression is n/2 + 3 = 7
Answer: The value of the hypotenuse is 61.
Step-by-step explanation:
So we are given a triangle with two known sides; two legs with values of 11 and 60. We have to use the Pythagorean Theorem to find the value of the hypotenuse.
The Pythagorean Theorem states that, "the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides".
This means that:
a^2 + b^2 = c^2
leg^2 + leg^2 = hypotenuse^2
So just by looking at that, we know that we can just substitute the values in:
11^2 + 60^2 = x^2
121 + 3600 = 3721
sqrt of 3721 = 61
So the hypotenuse value is 61.
