Answer:
G. All of these answers
Step-by-step explanation:
It would be all of them because some have to do with exercise and the others have to do with a plan for dieting and exercising.
<span><span>The more sources the better
Every researcher aims to have a standardized and uniform study when a study will be replicated or repeated for various reasons.
</span>The number of
accounts and evidential support of your thesis must be consistent and be
sufficient and succinct to the topic of study. These reasons and
evidential support should claim proximate with the pronounced
experimentation and variables which will be studied. In sense, the more
accounts and sources the better is your study, the greater it will stand
out and present itself. This is important for every thesis paper or
dissertation since these accounts provides and explicitly discusses the
studies that have been undertaken before which can greatly influence the
current study's credibility and reliability. </span>
Answer: A. y=x²-9x+20
Step-by-step explanation:
As we can see from the graph there are two x-intercepts: (4,0) (5,0)
The easiest way we can do, is we plug these two values into each of the choices.
A. y=x²-9x+20
(4, 0) YES
(5,0) YES
B. y=x²-8x+18
(4, 0) NO
(5, 0) NO
C. y=x²+9x+20
(4, 0) NO
(5, 0) NO
D. y=x²+x-12
(4, 0) NO
(5, 0) NO
Therefore, the answer should be y=x²-9x+20
Hope this helps!! :)
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Answer:
DE ≅ XY and XY ≅ YZ, then DE ≅ YZ
Thus, this statement is illustrated or validated by the 'Transitive Property of Segment Congruence'.
Step-by-step explanation:
We know that if two segments are congruent to the third segment, then they will be congruent to each other. This is called Transitive Property of Segment Congruence.
For example, Let suppose
LM ≅ AB and AB ≅ BC, then LM ≅ BC
30 ≅ 30 and 30 ≅ 30, then 30 ≅ 30
Thus, this validates the 'Transitive Property of Segment Congruence'.
Now Given
DE ≅ XY and XY ≅ YZ, then DE ≅ YZ
Thus, according to the above discussion, this statement is illustrated or validated by the 'Transitive Property of Segment Congruence'.