Question

Find the zeros of ply nomial x2-3 and verify the relation ship

Answer 1

Answer:

$x=\pm \sqrt{3}$

Step-by-step explanation:

Consider the given polynomial is

$P(x)=x^2-3$

We need to find the zeros of the given polynomial.

Now,

$P(x)=0$

$x^2-3=0$

Add 3 on both sides.

$x^2=3$

Taking square root on both sides.

$x=\pm \sqrt{3}$

Therefore, zeros of the polynomial P(x) are $-\sqrt{3} \text{ and }\sqrt{3}$.

To verify the relationship, put $x=\sqrt{3}$ in P(x).

$P(\sqrt{3})=(\sqrt{3})^2-3=3-3=0$

Put $x=-\sqrt{3}$ in P(x).

$P(-\sqrt{3})=(-\sqrt{3})^2-3=3-3=0$

Since P(x)=0 for both values, therefore relationship verified.