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2 years ago

Solve for k: 6=7k+1 K=

Mathematics

2 answers:

KonstantinChe [14]2 years ago

7 0

$\huge\color{purple}\boxed{\colorbox{black}{k=0.714}}$

$\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}$

$➺ \: 6 = 7k + 1$

$➺ \: 7k = 6 - 1$

$➺ \: 7k = 5$

$➺ \: k = \frac{5}{7}\\$

$➺ \: k = 0.714$

Therefore, the value of $k$ is $0.714$ .

$\large\mathfrak{{\pmb{\underline{\blue{To\:verify}}{\blue{:}}}}}$

$➺ \: 6 = 7k + 1$

$➺ \: 6 = 7 \times 0.714 + 1$

$➺ \: 6 = 5 + 1$

$➺ \: 6 = 6$

➺ L. H S. = R. H. S.

Hence verified.

$\bold{ \green{ \star{ \orange{Mystique35}}}}⋆$

Maslowich2 years ago

7 0

Answer:

5/7

Step-by-step explanation:

6=7k+1

-1 -1

--------------

5= 7k

Divide both sides by 7k

k= 5/7

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1 year ago

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Travis spends $2 in 10 pieces of gum to share with his friends. What is the correct unit rate?

DIA [1.3K]

Answer:

1 piece of gum= 20 cents

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2 years ago

Consider the number line with the plotted square roots.

ZanzabumX [31]

Answer: 19 Startroot and 24 endroot

Step-by-step explanation:

8 0

2 years ago

An 8-sided fair die is rolled twice and the product of the two numbers obtained when the die is rolled two times is calculated.

SCORPION-xisa [38]

Answer:

(a)See below

(b)I) 0.125 (ii)0.828125 (iii)0.234375 (iv) 0.625 (v)0.65625

Step-by-step explanation:

When an 8-sided die is rolled twice, the sample space is the set of all possible pairs (a,b) where a is the 1st outcome and b is the 2nd outcome.

The sample space is:

$[(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),(1, 7),(1, 8)\\(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),(2, 7),(2, 8)\\(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),(3, 7),(3, 8)\\(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),(4, 7),(4, 8)\\(5, 1), (5, 2), (5, 3), (5, 4), (5, 5),(5, 6),(5, 7),(5, 8)\\(6, 1), (6, 2), (6, 3), (6, 4)(6, 5),(6, 6),(6, 7),(6, 8)\\(7, 1), (7, 2), (7, 3), (7, 4)(7, 5),(7, 6),(7, 7),(7, 8)\\(8, 1), (8, 2), (8, 3), (8, 4)(8, 5),(8, 6),(8, 7),(8, 8)]$

The sample space of the product a*b of each pair forms the required possibility diagram.

This is given as:

$1, 2, 3, 4, 5, 6,7,8\\2, 4, 6, 8, 10, 12,14,16\\3,6,9,12,15,18,21,24\\4,8,12,16,20,24,28,32\\5,10,15,20,25,30,35,40\\6,12,18,24,30,36,42,48\\7,14,21,28,35,42,49,56\\8,16,24,32,40,48,56,64$

I) A prime number

The number of products that gives prime numbers = 8

The probability that the product is a prime number

$=\dfrac{8}{64}= \dfrac{1}{8}\\=0.125$

ii) Not a perfect square

Number of products that results in perfect squares =11

The probability that the product is not a perfect square

$=\dfrac{64-11}{64}= \dfrac{53}{64}\\=0.828125$

iii) A multiple of 5

Number of products that are multiples of 5=15

The probability that the product is a multiple of 5

$=\dfrac{15}{64}\\=0.234375$

iv) Less than or equal to 21

Number of products which are less than or equal to 21=40

The probability that the product less than or equal to 21

$=\dfrac{40}{64}=\dfrac{5}{8}\\=0.625$

v) Divisible by 4 or 6

Number of products divisible by 4 or 6= 42

The probability that the product is divisible by 4 or 6

$=\dfrac{42}{64}=\dfrac{21}{32}\\=0.65625$

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2 years ago

How many 5 digit numbers have the property that all their digits are ascending.

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Answer:

So, for the ascending order, there are only 9 digits to choose from, and hence, there are 9C5 ways to choose the 5 digits. So, there can be 9C5=126 5-digit no.s with their digits in an ascending order.

126 5

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2 years ago