All categories

1 year ago

Which of the following represents all solutions to the equation 1/3x^2 +10 = 7

Mathematics

2 answers:

fredd [130]1 year ago

5 0

Answer:

1 +-3i

Step-by-step explanation:

ahrayia [7]1 year ago

5 0

Answer:

answer is 1) x=±3i

Step-by-step explanation:

You might be interested in

Determine the rate of change between the points (-1,-1) and (1,-1).

AVprozaik [17]

Answer:

$\displaystyle m = 0$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinate Planes

Coordinates (x, y)
Slope Formula: $\displaystyle m = \frac{y_2 - y_1}{x_2 - x_1}$

Step-by-step explanation:

*Note:

Rate of change is slope.

Step 1: Define

Identify.

Point (-1, -1)

Point (1, -1)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m.

Substitute in points [Slope Formula]: $\displaystyle m = \frac{-1 + 1}{1 + 1}$
[Order of Operations] Simplify: $\displaystyle m = \frac{0}{2}$
Simplify: $\displaystyle m = 0$

4 0

2 years ago

(½ point for model; ½ point for correct simplified expression) (8x + 2) + (-9x + 7)

Alexxx [7]

Answer:

Simplified= −x+9

Step-by-step explanation:

5 0

2 years ago

I am having a hard time with this page if someone can help me i will appreciate it a lot!!

Allisa [31]

Answer:

#1 is It could be another girl or it could be a boy

#2 is Its could be another boy or it could be a girl.

The diagram should look like this:

BB. BG

GB GG

#4 is 4

#5 is 1

#6 is there is 1/2 a change the baby can be a girl and a 1/2 change the baby can be a boy. For both of them to be girls; it would be 1/4 chance.

5 0

2 years ago

ALGEBRA 2!!!!!!!!! SHOW YOUR WORK!!!!!!!!!!!!! Do f(g(x)) and g(f(x))

bezimeni [28]

$\bf f(x)=\cfrac{2x-3}{x+1}~\hspace{10em}g(x)=\cfrac{x+3}{2-x}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
f(~~g(x)~~)\implies \cfrac{2[g(x)]-3}{[g(x)]+1}\implies \cfrac{2\left( \frac{x+3}{2-x} \right)-3}{\left( \frac{x+3}{2-x} \right)+1}\implies
\cfrac{\frac{2x+6}{2-x}-3}{\frac{x+3}{2-x}+1}
\\\\\\
\cfrac{\frac{2x+6-6+3x}{2-x}}{\frac{x+3+2-x}{2-x}}\implies \cfrac{2x+6-6+3x}{2-x}\cdot \cfrac{2-x}{x+3+2-x}\implies \cfrac{5x}{5}\implies x$

$\bf \rule{34em}{0.25pt}\\\\
g(~~f(x)~~)\implies \cfrac{[f(x)]+3}{2-[f(x)]}\implies \cfrac{\frac{2x-3}{x+1}+3}{2-\frac{2x-3}{x+1}}\implies \cfrac{\frac{2x-3+3x+3}{x+1}}{\frac{2x+2-(2x-3)}{x+1}}
\\\\\\
\cfrac{2x-3+3x+3}{x+1}\cdot \cfrac{x+1}{2x+2-(2x-3)}\implies \cfrac{2x-3+3x+3}{x+1}\cdot \cfrac{x+1}{2x+2-2x+3}
\\\\\\
\cfrac{5x}{5}\implies x$