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1 year ago

Which of the following represents all solutions to the equation 1/3x^2 +10 = 7

Mathematics

2 answers:

fredd [130]1 year ago

5 0

Answer:

1 +-3i

Step-by-step explanation:

ahrayia [7]1 year ago

5 0

Answer:

answer is 1) x=±3i

Step-by-step explanation:

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Karen is 6 years older than her sister Michelle, and Michelle is 2 years younger than their brother David. If the sum of their a

ale4655 [162]

$K\ \rightarrow\ the\ Karen's\ age\\M\ \rightarrow\ the\ Michelles\ age \\D\ \rightarrow\ the\ David's\ age\\\\K=M+6\\M=D-2\ \ \ \Rightarrow\ \ \ D=M+2\\K+M+D=62\\\\(M+6)+M+(M+2)=62\\3M+8=62\\3M=54\ /:3\\M=18\ \ \ \Rightarrow\ \ \ K=18+6=24\ \ \ and\ \ \ D=18+2=20\\\\Ans.\ Michelle\ is\ 18,\ David\ is\ 20,\ Karen\ is\ 24.$

6 0

2 years ago

What is the measure for the following ∠? m∠BOA 20 40 60

kaheart [24]

Hello!

First, find angle BOA on the protractor. To do this, look for point B, point O, and point A.

Now, we see some markings that mark what degree point B and point A are at. Point B is marked at 60 degrees, and Point A 40 degrees.

Now, all that's left to do, is subtract the two measurements.

60 degrees - 40 degrees = 20 degrees

Therefore, your answer is 20.

Hope this helps!

8 0

3 years ago

CAN SOME ONE HELP ME ITS URGENT

aniked [119]

As we can observe from given information,

UT = ST

2x + 5 = x + 12

2x - x = 12 - 5

x = 7

now, let's solve for y

RU = RS

y - 4 = x + 5

y - 4 = 7 + 5

y = 12 + 4

y = 16

hope it helped...

5 0

2 years ago

Solve the matrix equation for a, b, c, and d. [1 2] [a b] [6 5][3 4] [c d]= [19 8]

Anit [1.1K]

Answer:

The answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

Step-by-step explanation:

$\bold{\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]}$

Solve the L.H.S part:

$\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\\\\\\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]$

After calculating the L.H.S part compare the value with R.H.S:

$\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]= \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]} \\\\$

$\to a+2c =6....(i)\\\\\to b+2d =5....(ii)\\\\\to 3a+4c =19....(iii)\\\\\to 3b+4d = 8 ....(iv)\\\\$

In equation (i) multiply by 3 and subtract by equation (iii):

$\to 3a+6c=18\\\to 3a+4c=19\\\\\text{subtract}... \\\\\to 2c = -1\\\\\to c= - \frac{1}{2}$

put the value of c in equation (i):

$\to a+ 2 (- \frac{1}{2})=6\\\\\to a- 2 \times \frac{1}{2}=6\\\\\to a- 1=6\\\\\to a =6 +1\\\\\to a = 7\\$

In equation (ii) multiply by 3 then subtract by equation (iv):

$\to 3b+6d=15\\\to 3b+4d=8\\\\\text{subtract...}\\\\\to 2d = 7\\\\\to d= \frac{7}{2}\\$

put the value of d in equation (iv):

$\to 3b+4 (\frac{7}{2})=8\\\\\to 3b+4 \times \frac{7}{2}=8\\\\\to 3b+14=8\\\\\to 3b =8-14\\\\\to 3b = -6\\\\\to b= \frac{-6}{3}\\\\\to b= -2$

The final answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

4 0

3 years ago

Helpppppppppppppppppppppppppppp

alexdok [17]

4/5. hopefully this helps

7 0

2 years ago

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