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mixas84 [53]
3 years ago
6

Plz help meh plz :}}

Mathematics
2 answers:
Arturiano [62]3 years ago
5 0
Answer: 15


Explanation: 3:5 x:25
Multiply 5 both sides
AVprozaik [17]3 years ago
4 0
18 if it’s not, then 21. I did ratios i long time ago so i don’t fully remember them.
You might be interested in
Cos(0.5)+cos(0.5+2(3.14159265))+cos(0.5+4(3.14159265))
aleksandr82 [10.1K]

Answer:

2.63274768567

Step-by-step explanation:

First, note that 3.1415... is p, so 2(3.1415...) is 2pi and 4(3.1415...) is 4pi.

2pi and 4pi are full rotations, which will lead to the same cosine (i.e. cos(x) = cos (x+2pi) = cos(x+4pi) = ... = cos (x+2k*pi)).

So, the expression equals cos0.5 + cos 0.5 + cos0.5 = 3cos0.5 = 3(0.87758256189) = 2.63274768567

I hope this helps! :)

7 0
3 years ago
HELP PLEASE! I WILL GIVE BRAINLIEST
rusak2 [61]

Answer:

13.89

Step-by-step explanation:

A^2+B^2=C^2

7^2+12^2=C^2

193 = C^2

193 square root = 13.89

6 0
2 years ago
What percentage of the data values represented on a box plot falls between the minimum value and the lower quartile?
Butoxors [25]

Answer:

first 25%

Step-by-step explanation:

A quartile is a quarter, so the first 25% falls between the minimum and lower quartile

4 0
3 years ago
Read 2 more answers
Write an equation of the line. Express the answer using either the general form or the​ slope-intercept form of the equation of
Georgia [21]

Answer:

y = x - 4

Step-by-step explanation:

The standard equation of a line is y = mx+b

m is the slope

b is the y intercept

Get the slope

Using the coordinate points (4, 0) and (0, -4)

m = -4-0/0-4

m = -4/-4

m = 1

Since the line cuts the y axis at y = -4, the y-intercept b = -4

Get the equation;

Since y = mx+b

y = 1x + (-4)

y = x - 4

This gives the required equation

7 0
2 years ago
The points A-1,-9) and K(5,1) are endpoints of a diameter of circle 5. Which equation represents circle S?
Lilit [14]

Answer:

A

Step-by-step explanation:

if (x1,y1) and (x2,y2) are the extremities of diameter,then eq. of circle is

(x-x1)(x-x2)+(y-y1)(y-y2)=0

reqd. eq. is (x+1)(x-5)+(y+9)(y-1)=0

x^{2} +x-5x-5+y^2+9y-y-9=0\\x^{2} -4x+y^2+8y-14=0\\compare with x^2+y^2+2gx+2fy+c=0\\center (-g,-f) \\radius r=\sqrt{g^2+f^2-c}

center is (2,-4)

r=√(2²+(-4)²-(-14))

=√(4+16+14)

=√(34)

eq. of circle is (x-2)²+(y+4)²=34

or

(x²-4x)+(y²+8y)=14

(x²-4x+4)+(y²+8y+16)=14+4+16

(x-2)²+(y+4)²=34

4 0
3 years ago
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