The second set of points is your answer.
Answer:
q = -13
Step-by-step explanation:
The given equation is:

Taking 2 as common from left hand side, we get:
![2(x^{2}-4x)=5\\\\2[x^{2} - 2(x)(2)]=5](https://tex.z-dn.net/?f=2%28x%5E%7B2%7D-4x%29%3D5%5C%5C%5C%5C2%5Bx%5E%7B2%7D%20-%202%28x%29%282%29%5D%3D5)
The square of difference is written as:
Equation 1
If we compare the given equation from previous step to formula in Equation 1, we note that we have square of first term(x), twice the product of 1st term(x) and second term(2) and the square of second term(2) is missing. So in order to complete the square we need to add and subtract square of 2 to right hand side. i.e.
![2[x^{2}-2(x)(2)+(2)^2-(2)^{2}]=5\\\\ 2[x^{2}-2(x)(2)+(2)^2]-2(2)^{2}=5\\\\ 2(x-2)^{2}-2(4)=5\\\\ 2(x-2)^2-8=5\\\\ 2(x-2)^{2}-8-5=0\\\\ 2(x-2)^{2}-13=0](https://tex.z-dn.net/?f=2%5Bx%5E%7B2%7D-2%28x%29%282%29%2B%282%29%5E2-%282%29%5E%7B2%7D%5D%3D5%5C%5C%5C%5C%202%5Bx%5E%7B2%7D-2%28x%29%282%29%2B%282%29%5E2%5D-2%282%29%5E%7B2%7D%3D5%5C%5C%5C%5C%202%28x-2%29%5E%7B2%7D-2%284%29%3D5%5C%5C%5C%5C%202%28x-2%29%5E2-8%3D5%5C%5C%5C%5C%202%28x-2%29%5E%7B2%7D-8-5%3D0%5C%5C%5C%5C%202%28x-2%29%5E%7B2%7D-13%3D0)
Comparing the above equation with the given equation:
, we can say:
p = 2 and q= -13
Since f(x) is written in vertex form with a negtive vertical expansion factor, we know it opens downward and the maximum is at the vertex, 3.
Since we have a graph of g(x), we can read the maximum from the graph, 4.
We can determine which function has the largest maximum by noting that the largest maximum is 4 and that it corresponds to function g(x).
Answer:
9.5 feet/ 1 second is your unit rate
Step-by-step explanation:
In order to make a unit rate you have to make the denominator 1 so it can be a whole number which means you divide by the denominator on both sides both numerator and denominator.
Answer:
Sine rule states that the ratio of a side of a triangle to the angle opposite the side is equivalent for all 3 sides and their respective opposite angles.

Thus, the side opposite ∠B is side AC, which is 10 units long. The side opposite ∠A is side BC, which is 8 units long. Substitute these values into the formula. (We are at line 2 of working)
Line 3: multiply both sides by 10 to find sinB
This would give us

This is can also be written as: (as seen in line 4)

To find the measure of angle B:

<em>~ Explanation for line 6 and onwards~</em>
The sine of an angle is positive in quadrants I and II. Since sinB is positive (≈0.69899), we are looking at these 2 quadrants. Since the reference angle is 44° rounded off to the nearest whole degree, in quadrant I, the angle would be 44° too.
In quadrant 2, the angle would be 180° -44°= 136°.