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Vinvika [58]
2 years ago
15

Condense log₂ 4 + log₂ 5

Mathematics
2 answers:
yawa3891 [41]2 years ago
7 0

Answer:   \log_2(20)

Work Shown:

\log_2(4) + \log_2(5)\\\\\log_2(4*5)\\\\\log_2(20)\\\\

The rule used is \log_{b}(\text{x}) + \log_{b}(\text{y}) = \log_{b}(\text{xy})

liberstina [14]2 years ago
3 0

\large{\textbf{Heya !}}

✏\large\sf{\bigstar Given:-} ✏

  • ㏒ expression = \sf{\log_24+\log_25}

✏\large{\sf{\bigstar To\quad Find:-} ✏

  • Condense the ㏒ into ONE expression - ?

✏\large{\sf{\bigstar Solution\quad steps:-}

<u></u>

<u>`To find what we want we need to apply ㏒ rules </u>

<u />

<u />

<u />

<u />\large{\sf{\longmapsto{log_ba+log_bc=log_b(ac)}

<u>using formula,</u>

<u />

<u />

<u />

<u />\large{\sf{\longmapsto{log_24+log_25=log_2(4\cdot5)}

<u>simplifying,</u>

<u />

<u />\large{\sf{\longmapsto{log_220}

<u>`hope it was helpful ! ~</u>

<u />

<u />

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A new American graduate is contemplating buying a Japanese, German, or an American car. No matter the type of car, he plans to b
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The best option is to buy Japanese Car.

Step-by-step explanation:

Fuel usage per year is 150000/ 8 = 18750 miles per year

Fuel cost (year 1 -8) = $3.0, $3.06, $3.12, $3.18, $3.25, $3.312, $3.38, $3.5

Japanese Car:

Fuel usage 18750 / 23 = 815 * $3 = $2446  

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Repair Cost (year 1 - 8) = $700, $721, $742, $764, $787, $811, $835, $860

Insurance cost (Year 1 - 8) = $700, $714, $728, $742, $757, $772, $788, $804

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Cost $35,000

Fuel usage 18750/20 = 937.5 * $3 per gallon = $2812.5.

Fuel charges (year 1 -8) = $2812, $2913, $2986, $3011. $3098, $3124, $3176, $3208

Repair Cost (year 1 - 8) = $800, $894, $921, $978, $1109, $1176, $1207, $1301

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Cost = $45,000

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Insurance cost (Year 1 - 8) = $850, $867, $884, $902, $920, $938, $957, $976

Present value of cost at 5% = 27105.73

Cost of car is $45,000

Total cost = $72105.

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cos(2x) cos(x) + sin(2x) sin(x)  (3)

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