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kramer
3 years ago
8

Hi people if someone gives me a hint please. Show algebraically that the product of two consecutive numbers is always even l wro

te n (n+1) is always an even number But doesnt recognise it as 100% right thanks for any help
Mathematics
1 answer:
Andru [333]3 years ago
8 0

Step-by-step explanation:

Consider the following rules.

even + odd = odd

even - odd = odd

even × odd = even

even ÷ odd = even (if divisible)

Now for the two consectives terms...

One will surely be even and the other, odd.

So using the rule

Their product will always be odd

Hope it helps....

BRAINLIEST PRETTY PLEASE!!

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What index of m will be 1/m​
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5 0
3 years ago
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A California water company has determined that the average customer billing is $1,250 per year and the amounts billed have an ex
Tcecarenko [31]

Answer:

a)

Mean \mu = \dfrac{1}{\lambda }= 1250

\lambda = \dfrac{1}{1250}

b)

P(X > 5000) = 0.0183

c)

P(X > 1250) =0.3679

Step-by-step explanation:

From the given information:

a.)

Mean \mu = \dfrac{1}{\lambda }= 1250

\lambda = \dfrac{1}{1250}

Let consider X to be a random variable that follows an exponential distribution; then:

P(X) = 1 - e^{- \lambda x}   since \lambda > 0

b.)

The required probability that a random chosen customer would spend more than $5,000 can be computed as:

P(X > 5000) = 1  - \bigg [ 1 - e ^{- \dfrac{5000}{1250}}  \bigg]

P(X > 5000) =e^  {-4

P(X > 5000) = 0.0183

c.)

P(X > 1250) = 1  - \bigg [ 1 - e ^{- \dfrac{1250}{1250}}  \bigg]

P(X > 1250) =e ^{- 1

P(X > 1250) =0.3679

7 0
3 years ago
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