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kramer
3 years ago
8

Hi people if someone gives me a hint please. Show algebraically that the product of two consecutive numbers is always even l wro

te n (n+1) is always an even number But doesnt recognise it as 100% right thanks for any help
Mathematics
1 answer:
Andru [333]3 years ago
8 0

Step-by-step explanation:

Consider the following rules.

even + odd = odd

even - odd = odd

even × odd = even

even ÷ odd = even (if divisible)

Now for the two consectives terms...

One will surely be even and the other, odd.

So using the rule

Their product will always be odd

Hope it helps....

BRAINLIEST PRETTY PLEASE!!

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What is the value of y when x = 3. y = 12x
alexandr1967 [171]
We have the equation y = 12x. And we know the value of x. The value of x is 3.
So, if we replace the x variable with the value of x, then we can solve the equation.

y = 12(3)
y = 36

So, the answer is 36.
7 0
3 years ago
Read 2 more answers
If your taxable income puts you in the 25% marginal tax bracket is it ?
denis23 [38]
The answer to your question is A. because your tax would be 25% of your taxable income. I'm in personal finance and i just had a question like this the other day.
3 0
3 years ago
1 point
galina1969 [7]

Answer:

(B) 20

Step-by-step explanation:

Let small puppet be represented by-----------------s

Let large puppet be represented by-----------------l

Total number of puppets expression will be: s+l =25---------a

The expression for total costs will be : 1$ s + $2l=$30-------b

Equation a can be written as; s= 25-l ------------c

Use equation c in equation b as

$1( 25-l )+$ 2l = $30

25-l + 2l = 30

25+l =30

l= 30-25 =5

l, large puppets = 5

s, small puppets = 25-5 = 20

Answer choice A is incorrect because 25 is the total number of all puppets

Answer choice C and D are incorrect because the numbers are less that that of small puppets.

3 0
3 years ago
Can someone please answer. There is one problem. There is a picture. Thank you!
jonny [76]
SA=4pir^2
78.54km^2=SA
78.54=4pir^2
divide both sides by 4
19.635=pir^2
aprox pi=3.14 so divide both sides by 3.14
6.25318=r^2
sqrt both sides
2.50063=r
round
radius=2.5km

this question is flawed in that it gives the wrong units

answer is the option with 2.5 in it
2nd one
5 0
3 years ago
Please help me with both questions!!!!​​
Naya [18.7K]

Answer:

Step-by-step explanation:

16.

points are (0,-3),(2,1),(4,-3)

eq. of line through (0,-3) and (2,1) is

y+3=\frac{1+3}{2-0}(x-0)

or y+3=2x

2x-y=3

as the line is dotted so either < or >.

consider 2x-y>3

put x=0,y=0

0>3

which is not possible .

(0,0) does not satisfy the inequality

Hence shaded region is the required region.

now eq of line through (2,1)and (4,-3) is

y-1=\frac{-3-1}{4-2}(x-2)

y-1=-2(x-2)

y-1=-2x+4

2x+y=5

it is also a  dotted line so either < or >

consider 2x+y<5

put x=0,y=0

0<5

which is true.

so (0,0) satisfy this inequality.

so the two inequalities are

2x-y>3

and 2x+y<5

17.

consider the points (0,4),(2,3),(4,4)

eq. of line through (0,4) and (2,3) is

y-4=\frac{3-4}{2-0}(x-0)

y-4=-1/2(x)

2y-8=-x

or x+2y=8

as the line is solid

so either≤ or ≥

consider x+2y≥8

put x=0,y=0

0≥8

which is impossible.

(0,0) does not satisfy the graph.

which is true as graph lies above the line.

again eq. of line through (2,3) and (4,4) is

y-3=\frac{4-3}{4-2}(x-2)

y-3=1/2(x-2)

2y-6=x-2

x-2y=-4

consider x-2y≤-4

put x=0, y=0

0≤-4

which is impossible.

so (0,0) does not satisfy the graph.

so inequality is true as shaded portion is above and left of the line.

so two inequalities are

x+2y≥ 8

and x-2y≤-4

5 0
3 years ago
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