A geologist in South America discovers a
1 answer:
Answer:
This is a radioactive decay / half-life problem.
Initial amount of C 14 = 100% Present Amount = 57%
k = .0001 (that value should be negative)
Nt = No * e^ (k*t)
You need to solve that equation for "time" (equation attached)
time = natural log (Ending amount / Starting Amount) / k
time = natural log (57% / 100%) / -.0001
time = ln (.57) / -.0001
time = -.56211891815 / -.0001
time = 5,621.2 years (age of the bird skeleton)
These problems are quite complicated but I think I know this pretty well.
Need to know more? Visit my website (it's on the graphic).
Step-by-step explanation:
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Wouldn't it be zero? because only 0 is less than 2 in this case
Answer:
13
Step-by-step explanation:
The average rate of change of f(x) in the closed interval [ a, b ] is
Here [ a, b ] = [2, 6 ]
f(b) = f(6) = 6² + 5(6) - 8 = 36 + 30 - 8 = 58
f(a) = f(2) = 2² + 5(2) - 8 = 4 + 10 - 8 = 6
Hence
average rate of change = =
= 13