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mel-nik [20]
2 years ago
13

Determine the five-number summary for this data set, taking into account any outliers. 10 13 15 12 12 4 12 17 12 13 15 18 10 11

20 19 Tiles 11.5 13 16 20 10 12.5 17
Mathematics
1 answer:
TiliK225 [7]2 years ago
3 0

The value of the median, lower and upper quartile

  • Median = 21.5
  • lower quartile = 12
  • upper quartile = 29

<h3>What is the five-number summary for this data set?</h3>

The minimum value = 10

The maximum value = 38

The median is the value that is found in the center of the data when it is ordered from lowest to highest. In the event that there is no value that precisely corresponds to the center, the value will be determined by taking the average of the values that are located on each side of the middle.

10  11  12  15  19  24  27  29  33  38

Median = 21.5

The intermediate value of the data that is located to the left of the median is known as the lower quartile.

10  11  12  15  19

lower quartile = 12

The intermediate value of the data that is located to the right of the median is known as the upper quartile.

24  27  29  33  38

upper quartile = 29

In conclusion, the 5 number summary is 10, 12, 21.5, 29, 38 → A

Read more about median

brainly.com/question/28060453

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An open-top box with a square base is to have a volume of 4 cubic feet. Find the dimensions of the box (in ft) that can be made
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Answer:

The dimension of box=2ft\times 2ft\times 1ft

Step-by-step explanation:

We are given that

Volume of box=4 cubic feet

Let x be the side of square base and h be the height of box

Volume of box=lbh=x^2h

4=x^2h

h=\frac{4}{x^2}

Now, surface area of box,A=x^2+4xh

A=x^2+4x(\frac{4}{x^2})=x^2+\frac{16}{x}

\frac{dA}{dx}=2x-\frac{16}{x^2}

\frac{dA}{dx}=0

2x-\frac{16}{x^2}=0

2x=\frac{16}{x^2}

x^3=8

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Substitute x=2

\frac{d^2A}{dx^2}=2+\frac{32}{2^3}=2+4=6>0

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Height of box,h=\frac{4}{2^2}=1 ft

Hence, the dimension of box=2ft\times 2ft\times 1ft

5 0
3 years ago
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