Answer:
I think its the third one but i might be wrong
Step-by-step explanation:
Last time I checked- it was a rhombus.
Answer:
The upper bound for the perimeter of the rectangle = 427.76 cm
Step-by-step explanation:
To obtain the upper bound for the perimeter, we need to first obtain the upper bound for the Length and Breadth of the rectangle.
Since, these dimensions were rounded to the nearest 1 decimal place, we can write down their ranges
Length = 127.3 cm
Width = 86.5 cm
Length can range from 127.25 cm to 127.34 cm
Breadth can range from 86.45 cm to 86.54 cm
The upper bound for the Length and Breadth of the rectangle are this 127.34 cm and 86.54 cm respectively.
Perimeter = 2 (L + B)
Upper bound of the perimeter
= 2 × (127.34 + 86.54)
= 2 × 213.88
= 427.76 cm
Hope this Helps!!!
X+25=60x=60-25,x=35. Hope this helped
The answer is 141.35 ft²
Before the first break, it was painted:
150 ft² ÷ 2 = 75 ft²
Now it's left:
150 ft² - 75 ft² = 75 <span>ft²
Before the second break, it was painted:
75 </span>ft² ÷ 2 = 37.5 <span>ft²
Now it's left:
75 </span>ft² - 37.5 ft² = 37.5 <span>ft²
Before the third break, it was painted:
37.5 </span>ft² ÷ 2 = 18.75 <span>ft²
</span><span>Now it's left:
</span>37.5 ft² - 18.75 ft² = 18.75 <span>ft²
</span>
<span>Before the fourth break, it was painted:
</span>18.75 ft² ÷ 2 = 9.375 <span>ft²
</span><span>Now it's left:
</span>18.75 ft² - 9.375 ft² = 9.375 <span>ft²
</span>
<span>Before the fourth break, it was painted:
</span>9.375 ft² ÷ 2 = 4.6875 <span>ft²
</span><span>Now it's left:
</span>9.375 ft² - 4.6875 ft² = 4.6875 ft²
Now, we will sum what he painted for now:
75 ft² + 37.5 ft² + 18.75 ft² + 9.375 ft² 4.6875 ft² = 141.3125 ft² ≈ 141.35 ft²
When the painter takes his fifth break, there will be <span>141.35 ft² of the wall painted.</span>
