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Phoenix [80]
3 years ago
11

To find the optimal solution to a linear programming problem using the graphical method, a. find the feasible point that is the

farthest away from the origin. b. find the feasible point that is at the highest location. c. find the feasible point that is closest to the origin. d. None of these are correct.
Mathematics
1 answer:
Elenna [48]3 years ago
3 0

Answer:

The correct option D

Step-by-step explanation:

Linear Programming deals with the optimization (maximum or minimum) of a function of variables, known as objective function, subject to a set of linear equations and/or inequalities known as constraints.

Graphical Method can be used only for Linear Programming Problem with only two variables. The graphical method provides a pictorial representation of the solution process and a great deal of insight into the basic concepts used in solving large Linear Programming Problems.

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8th grade math Ik but I do need help though
kramer

Answer:

x =-4

Step-by-step explanation:

4x+9 = -2x-15

Add 2x to each side

4x+2x +9 = -2x+2x-15

6x+9 = -15

Subtract 9 from each side

6x +9-9=-15-9

6x = -24

Divide each side by 6

6x/6 = -24/6

x = -4

7 0
3 years ago
Cual es la de Raiz de 2000
serg [7]

2000 | 2

1000 | 2

500 | 2

250 | 2

125 | 5

25 | 5

5 | 5

1

√2000 = √2².√2².√5².√5

√2000 = 2.2.5√5

√2000 = 20√5

(aproximadamente 44.72135955)

4 0
3 years ago
Factor
stellarik [79]
C on that one which is the correct answer
5 0
3 years ago
Read 2 more answers
Does (-2)^n/( 3^n+1) converge or diverge?
hodyreva [135]
\left|\dfrac{(-2)^n}{3^n+1}\right|=\dfrac{2^n}{3^n+1}

As n\to\infty, the sequence a_n=\left(\dfrac23\right)^n converges to zero.

If you're talking about the infinite series

\displaystyle\sum_{n\ge0}\dfrac{(-2)^n}{3^n+1}

well we've shown by comparison that this series must also converge because we know any geometric series \sum\limits_n r^n will converge as long as |r|.
3 0
2 years ago
Please help
user100 [1]

Answer:

Length of garden will be 30 metres.

Step-by-step explanation:

Let the Width of garden be x metres.

then,

Length of garden will be (x+6) metres.

Area = Length × Breadth

720 = x X (c+6)

720 = x²+6x

0 = x²+6x-720

As we can see above equation is a quadratic equation in the form of ax²+bx+C.

so,

=  \frac{ - b ±  \sqrt{{b}^{2} - 4ac}  }{2a}  \\ =   \frac{ - 6 ±   \sqrt{{6}^{2} - 4 \times 1 \times  - 720}  }{2}  \\ =    \frac{ - 6 ±  \sqrt{36 + 2880} }{2}  \\  =   \frac{ - 6 ±  \sqrt{2916} }{2}  \\  =   \frac{ - 6 ± 54}{2}\\= \frac{-6+54}{2} ... \frac{ - 6 - 54}{2}  \\  =  \frac{48}{2} ... \frac{ - 60}{2}  \\  = 24... - 30

One of the Roots of the Quadratic equation is 24 and other is -30.

And as we know width of any garden cannot be negative so the width of garden will be 24 metres.

As we got the width,

adding 6 to it will give us the Length,

So,

24 metres + 6 = 30 metres.

Length of the garden is 30 metres.

Hope It Helped You ;)

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@khuturr_

8 0
3 years ago
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