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vichka [17]
3 years ago
15

-3,1,5,13 find the sequence

Mathematics
1 answer:
geniusboy [140]3 years ago
3 0

Answer:

add 4 twice then add 8 twice

hope this helps

have a good day :)

Step-by-step explanation:

You might be interested in
Jan's house has four leaking taps. An average of 34 cL of water leaks from each tap every day. How many litres of water is lost
pshichka [43]

Answer: 42.16l

Step-by-step explanation:

First, we should note that August has 31 days. Since Jan's house has four leaking taps and an average of 34 cL of water leaks from each tap every day. The four taps will leak (34 × 4) = 136 cL everyday.

The amount of litres of water that is lost from these four taps in August would be:

= 136cL × 31

= 4216 cL

= 42.16L

We should note that 100cL = 1L

7 0
3 years ago
Find the number of elements in A 1 ∪ A 2 ∪ A 3 if there are 200 elements in A 1 , 1000 in A 2 , and 5, 000 in A 3 if (a) A 1 ⊆ A
lina2011 [118]

Answer:

a. 4600

b. 6200

c. 6193

Step-by-step explanation:

Let n(A) the number of elements in A.

Remember, the number of elements in A_1 \cup A_2 \cup A_3 satisfies

n(A_1 \cup A_2 \cup A_3)=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)

Then,

a) If A_1\subseteq A_2, n(A_1 \cap A_2)=n(A_1)=200, and if A_2\subseteq A_3, n(A_2\cap A_3)=n(A_2)=1000

Since A_1\subseteq A_2\; and \; A_2\subseteq A_3, \; then \; A_1\cap A_2 \cap A_3= A_1

So

n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-200-200-1000-200=4600

b) Since the sets are pairwise disjoint

n(A_1 \cup A_2 \cup A_3)=\\n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\200+1000+5000-0-0-0-0=6200

c) Since there are two elements in common to each pair of sets and one element in all three sets, then

n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-2-2-2-1=6193

8 0
2 years ago
63% of 300 is what number ​
PolarNik [594]

Answer:

189

Step-by-step explanation:

You take 63% make it a decimal by dividing it by 100 and then you multiply it with 300. 300*.63=189.

6 0
3 years ago
Read 2 more answers
Evaluate.
Radda [10]

Step-by-step explanation:

-| 12/3 - 1| 2-(-3)

-|12-3/3|5

-5|9/3|

-5|3|

-5×3 & -5×-3

-15 & 15

I think it is the answer

6 0
1 year ago
angle EFG and angle GFH are a linear pair, m angle GFH= 2n+38 and m angle GFH=2n+38. what are m angle EFG and m angle GFH
motikmotik

Answer:

Part 1) m∠EFG=94°

Part 2) m∠GFH=86°

Step-by-step explanation:

we know that

m∠EFG+m∠GFH=180° -----> by linear pair (given problem)

we have

m∠EFG=3n+22

m∠GFH=2n+38

substitute the values

(3n+22)°+(2n+38)°=180°

Solve for n

(5n+60)=180

5n=180-60

5n=120

n=24

<em>Find the measure of angle EFG</em>

m∠EFG=3n+22

substitute the value of n

m∠EFG=3(24)+22=94°

<em>Find the measure of angle GFH</em>

m∠GFH=2n+38

substitute the value of n

m∠GFH=2(24)+38=86°

5 0
3 years ago
Read 2 more answers
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