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3 years ago

16 is the geometric mean of 8 and what other number?

Mathematics

1 answer:

zepelin [54]3 years ago

8 0

It is also the geometric mean of 4

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A marker costs $0.99. A pad of paper costs $1.25 more than the marker, which is a more reasonable estimate for the total cost of

andrew11 [14]

Answer:

Step-by-step explanation:

Because you have to also think about tax of the item. Plus add them both up and it costs $2.24 without tax. Which means it's already above $2.

8 0

3 years ago

In a science experiment, Shelly has to weigh a compound in grams. The balance in her school measures in milligrams (mg). Shelly

exis [7]

Answer:

8.45 grams

Step-by-step explanation:

In a science experiment, Shelly has to weigh a compound in grams. The balance in her school measures in milligrams (mg). Shelly finds that the weight of the compound is 8,450 mg. What is the value in grams (g) that Shelly should enter?

1 mg = 0.001 g

8450 mg = x

Cross Multiply

= 8450 × 0.001 g

= 8.45 g

Therefore, Shelly should enter 8.45 grams

7 0

3 years ago

The cost of K-12 education per student was $2200 in 1978 and increased to $10,300 in 2008. (Source: Department of Education). (a

kobusy [5.1K]

Answer: $C=270x+2200$

Step-by-step explanation:

Given

Cost per student in the year 1978 is $2200

The cost increases to $10,300 in 2008

Suppose $C=mx+a$ is the linear equation defining the cost per student after x years

Substitute the value for 1978

$\Rightarrow 2200=m(0)+c\\\Rightarrow c=2200$

After 30 years it becomes

$\Rightarrow 10,300=m(30)+2200\\\Rightarrow 30m=8100\\\Rightarrow m=270$

Thus, the linear equation becomes

$\Rightarrow C=270x+2200$

6 0

3 years ago

What's the cube root of 2744000

Paraphin [41]

The cube root of 2744000 is 140

4 0

4 years ago

Can someone help me and explain? I will mark brainlest. ♡

Sedbober [7]

Answer:

$p'(4) = -3$

$q'(8) = \frac{1}{4}\\$

Step-by-step explanation:

For p'(4):

$p(x) = f(x)g(x) \\ p'(x) = \frac{d}{dx}(f(x)g(x)) \\ p'(x) = f'(x)g(x) +f(x)g'(x)$

$p'(4) = f'(4)g(4) + f(4)g'(4) \\ p'(4) = (-1)(3) +(7)(0) \\ p'(4) = -3$

For q'(8):

$q(x) = \frac{f(x)}{g(x)} \\ q'(x)= \frac{d}{dx}(\frac{f(x)}{g(x)}) \\ q'(x) = \frac{f'(x)g(x) -f(x)g'(x)}{{g(x)}^2}$

$q'(8) = \frac{f'(8)g(8) -f(8)g'(8)}{{g(8)}^2} \\ q'(8) = \frac{(2)(2) -(6)(\frac{1}{2})}{{2}^2} \\ q'(8) = \frac{4 -3}{4} \\ q'(8) = \frac{1}{4}$

4 0

3 years ago

Read 2 more answers