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Sergio039 [100]
2 years ago
7

Please help me on this question!!

Mathematics
2 answers:
grigory [225]2 years ago
8 0

Answer:

B

Step-by-step explanation:

The domain is the set of input values, which is typically shown on the horizontal axis.

aalyn [17]2 years ago
6 0

The answer is B.

The domain of the function refers to the possible values of the horizontal axis of the graph.

Hence, the domain is : 6 ≤ g ≤ 12

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12 less that 5 times a number is greater than or equal to 6 more than twice the number
11111nata11111 [884]

Answer:

5x-12 > with the _ on the bottom 6+2x

Step-by-step explanation:

x is the number/variable

3 0
3 years ago
3/8-(-51/4) simplest form
Ratling [72]

Answer:

13 1/8

Step-by-step explanation:

3/8-(-51/4)

Subtracting a negative is like adding

3/8 + 51/4

get a common denominator

3/8+ 51/4 *2/2

3/8 + 102/8

105/8

8 goes into 105 13 times with 1 left over

13 1/8

3 0
3 years ago
Which fraction is equivalent to negative 3 over 7 ? (5 points) negative 7 over 3 3 over negative 7 3 over 7 7 over 3
ivanzaharov [21]

Answer: 0.06

27/50

1/64

I am not sure but I think it is 1/36

3⁵

Idaho has the smallest population.

0.000857

 1.414213562..

1.5 x 10⁸

.16

3/32

6.2

 29/30

I am not sure

-1/6

4/9

2.25

.265

Step-by-step explanation:

6 0
3 years ago
What is the width of todors area model? <br> 10x exponent2 -5x 15
mafiozo [28]

Answer:

The width of the area model is equal to

(2x^2-x+3)\ units

Step-by-step explanation:

<u><em>The complete question is</em></u>

Todor was trying to factor 10x^2-5x+15 he found the greatest common factor of these terms was 5 what is the width

we know that

The area of a rectangular model is given by the formula

A=LW ----> equation A

where

L is the length

W is the width

we have

A=10x^2-5x+15

Factor the expression

A=5(2x^2-x+3)

substitute the value of the Area in the equation A

5(2x^2-x+3)=LW

In this problem

The greatest common factor of these terms is the length (L=5 units)

so

we can say that the width is equal to (2x^2-x+3)

therefore

The width of the area model is equal to

(2x^2-x+3)\ units

5 0
3 years ago
Hey puddin could ya help me !?- What is the length of segment AB?
ycow [4]

Answer:

AB = 4\sqrt{5}

Step-by-step explanation:

Calculate AB using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = A(6, 2) and (x₂, y₂ ) = B(0, 10)

AB = \sqrt{(0-6)^2+(10-2)^2}

     = \sqrt{4^2+8^2}

    = \sqrt{16+64}

    = \sqrt{80} = 4\sqrt{5} ← exact length

4 0
3 years ago
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