Answer:
The cosine of the angle is <u>positive</u>
The sine of the angle is <u>negative</u>
Step-by-step explanation:
We are given that
angle lies in fourth quadrant
and we know that
In first quadrant:
sin is positive
cos is positive
In second quadrant:
sin is positive
cos is negative
In third quadrant:
sin is negative
cos is negative
in fourth quadrant , cosine of angle is always positive
and sine of angle is always negative
so,
The cosine of the angle is <u>positive</u>
The sine of the angle is <u>negative</u>
1 whole thing = 6 sixths
3 whole things = 18 sixths
1 third of a whole thing = 2 sixths of it
3 wholes plus 1 third = 18 sixths plus 2 sixths = 20 sixths
Answer:
1) m ∠B = 132°
2) m ∠B = 113°
Step-by-step explanation:
1. In triangle ABC, m ∠A=36, and m ∠C=12. Calculate m ∠B.
We are given measure of 2 angles and we need to find the third angle.
We know that, sum of angles of triangle = 180°
We can write as:
∠A + ∠B + ∠C = 180°
Now put m ∠A=36 and m ∠C=12, to find m ∠B
So, we get m ∠B = 132°
2. In triangle ABC, m ∠A=40, and m ∠C=27. Calculate m ∠B.
We are given measure of 2 angles and we need to find the third angle.
We know that, sum of angles of triangle = 180°
We can write as:
∠A + ∠B + ∠C = 180°
Now put m ∠A=40 and m ∠C=27, to find m ∠B
So, we get m ∠B = 113°
Answer:
Step-by-step explanation:
The line can be written as
Since the line is contained in the plane, if we take any two points of this line they will lie in the plane.
Give values for t =0 and 1
We get two points (x,y,z) as (1,3,0) and (3,2,1)
Now we have another non collinearpoint (1,1,1) (given)
The plane equation can be written using these 3 points using the determinant.
x-x1 y-y1 z-z1
x2-x1 y2-y2 z2-z1
x3-x1 y3-y1 z3-z1 =0
Substitute the values form the points.
We get
Expand the determinant as
(x-1)(-1+2)-(y-3)(2-0)+z(-4-0) =0
x-1-2y+6-4z =0
x-2y-4z+5 =0