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schepotkina [342]
2 years ago
14

The number of gallons of gas Connie’s car, g, uses is directly proportional with the number of miles she drives, m. Last week, s

he drove 469.8 miles and used 14.5 gallons of gas. Which equation would best represent the problem?
Mathematics
1 answer:
stellarik [79]2 years ago
6 0

The equation which represent the problem is 14.5 = 469.8k.

<h3>What is Equation?</h3>

An equation is a mathematical statement with an 'equal to =' symbol between two expressions that have equal values.

Here, As given in question

The number of gallons of gas Connie’s car, g, uses is directly proportional with the number of miles she drives, m.

                                    g α m

                                     g = km     ............(i)

g = 14.5 gallons of gas          m = 469.8 miles

                                  14.5 = k X 469.8

                                  14.5 = 469.8k

Thus, the equation which represent the problem is 14.5 = 469.8k.

Learn more about Equation from:

brainly.com/question/2263981

#SPJ1

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---------------------------------------------

Part A

The graph of y >= -3x+3 will have a solid boundary line and the shading will be above the boundary line.

The boundary line y = -3x+3 has a negative slope so it moves down as you read it from left to right. It goes through the points (0,3) and (1,0)

--------------

The graph of y < (3/2)x - 6 will have a dashed or dotted boundary line. The shading is below the boundary.

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If you graph both y >= -3x+3 and y < (3/2)x - 6 together, you get what you see in the attached image. This solution shaded region is the result of the overlapping prior shaded regions. 

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Part B

Plug (x,y) = (-6,3) into each inequality to see if we get a true inequality or not

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Let's check the other inequality just for the sake of completeness
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this is also false. The value -15 is smaller than 3, since it is to the left of 3

We're given more evidence that (-6,3) is NOT in the solution area. It is outside of both shaded areas. 

7 0
3 years ago
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valentina_108 [34]
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