Answer:
The line crosses the x-axis at the point (-3.5,0).
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
The other end point would be (5,-11)
Answer:
FH ~ 10.02
Step-by-step explanation:
1. Approach
One should first find the circumference of the given circle. Then one should find how large the fraction of the circumference one is supposed to find is. Finally, one should multiply the fraction of the circumference one is supposed to find by the total circumference.
2. Circumference of the circle
The formula for circumference is;
π
Substitute in the given values;
It is given that the radius is, hence
2 (7) π
14π
3. Find the fraction of the circumference one is supposed to find
It is given that the angles over the measure of the total degrees of angles in a circle are equal to the arc surrounding the angles of the circumference. Essentially;

Substitute in the given information and solve;

arc = 
arc = 
arc ~ 10.02
9/27 is equivalent to 2/27