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2 years ago

What divided by 4 equals 9/4 ( 9/4= Divided by 4 )

Mathematics

1 answer:

Ann [662]2 years ago

5 0

Answer

16/9

Step-by-step explanation:

I don't know if this is right or not and I'm sry if its wrong

but 16/9 divided by 4 = 9/4

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3xy'+y=12x find general solution

Eduardwww [97]

The equation is linear, as you can write

$3xy'+y=12x\implies y'+\dfrac1{3x}y=4$

An integrating factor would be

$\mu(x)=\exp\left(\displaystyle\int\frac{\mathrm dx}{3x}\right)=x^{1/3}$

Multiplying both sides of the ODE by this yields

$x^{1/3}y'+\dfrac1{3x^{2/3}}y=4x^{1/3}$

where the LHS is a derivative:

$\dfrac{\mathrm d}{\mathrm dx}\left[x^{1/3}y\right]=4x^{1/3}$

Integrating both sides, we get

$x^{1/3}y=4\displaystyle\int x^{1/3}\,\mathrm dx$
$x^{1/3}y=3x^{4/3}+C$
$y=3x^{3/3}+Cx^{-1/3}=3x+\dfrac C{x^{1/3}}$

5 0

3 years ago

Apply each of the four counting/sampling methods (with replacement and with ordering, without replacement and with ordering, wit

dusya [7]

Answer:

Step-by-step explanation:

I will illustrate this solution with a unique birthday party situation between Jane (the celebrant) and her 10 friends.

In the said party , we will assume that Jane only has 5 chocolates to share among her friends

i. Assuming that the 5 chocolates are of the same type, if she doesn't want to give any friend more than one piece of chocolate, the situation here is said to be WITHOUT REPLACEMENT & UN-ORDERED

n = 10 and k = 5

Total number of possible combinations becomes,

$(\left {n} \atop {k}} \right. )=(\left {10} \atop {5}} \right. )=252$

ii. Assuming that the 5 pieces of chocolate are of the same type and she is willing to give a friend more than one piece of chocolate, the situation is said to be WITH REPLACEMENT & UN-ORDERED

n = 10 and k = 5

Total number of possible combinations becomes,

$(\left {n+k-1} \atop {k}} \right. )=(\left {14} \atop {5}} \right. )=2002$

iii. Assuming that the 5 pieces of chocolate are of different types and she isn't willing to give any friend more than one piece of chocolate, the situation is said to be WITHOUT REPLACEMENT & ORDERED

n = 10 & k = 5

Total number of possible combinations becomes,

$P\left {n} \atop {k}} \right=P\left {10} \atop {5}} \right. =30240$

iv. Assuming the the 5 pieces of chocolate are of different types, if she is willing to give a friend more than one piece of chocolate, the situation is said to be WITH REPLACEMENT & ORDERED

n = 10 AND k = 5

Total number of combinations becomes

$n^k=10^5=100,000$

Sampling with replacement means that one friend can be sampled more than once i.e: A friend receives a piece of chocolate more than once

The order dictates how the sampling is applied.

3 0

3 years ago

If ABC ~ DEF and the scale factor from ABC to DEF is 1/5, what are the lengths of DE , EF and DF , respectively?

crimeas [40]

Answer:

option a (2,2,5)

Step-by-step explanation:

First we have to notice that it tells us that the scale is 1/5.

This means that the measures of the new triangle will be 5 times smaller than those of the other triangle.

Now we just have to take the measurements of the sides of the triangle and multiply them by 1/5 or divide them by 5

AB = 10 DE = 10/5 = 2

BC = 10 EF = 10/5 = 2

AC = 25 DF = 25/5 = 5

DE = 2

EF = 2

DF = 5

(2, 2, 5)

7 0

3 years ago

Quinton answered 90% of his test questions correctly. Quinton answered 54 questions correctly.

snow_tiger [21]

There would be 60 questions on the test.

90%=54
1%= 54/90 = 6/10
100%= 6×100/10 =6×10=60

7 0

3 years ago

Pls need help w this question

zhuklara [117]

Ok here me out.... 25

4 0

3 years ago