Answer:
Ok, we know that we can write a horizontal translation as:
y' = f(x - A)
where if A is positive, this moves the graph of f(x) A units to the right.
Why is this?
Ok, let's compare:
y = f(x)
and
y' = f(x - A)
in y, when x = 0 we have f(0).
While to have this same point in y', we need to evaluate in x = A.
f(A - A) = f(0).
Then the value f(0) is now at x = A, this means that the point moved A units to the right.
And you can do this for all the values, so you will find that the entire graph of f(x) has ben moved A units to the right.
0.15 is bigger, this is because the 0.05 in 0.15 has more value than 0.02 in 0.125, even though it has a third digit.
Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
Answer:
14
Step-by-step explanation:
Complementary angles = 90
x+y =90
y=x+24
substitute this in to the equation
x+x+24=90
2x+24=90
subtract 24 from each side
2x = 66
divide by 2
x=33
y = 33+24
y=57
Answer: 33, 57
