Answer: Your correct don't change your answer it's (B.
Explanation:
Answer: Saturated fatty acids are one of the two major categories of fat. Common dietary saturated fatty acids include stearic acid, palmitic acid, myristic acid, and lauric acid.
Answer:
22.13g
Explanation:
We'll begin by writing a balanced equation for the reaction. This is illustrated below:
2C2H2 + 5O2 —> 4CO2 + 2H2O
Next, we'll calculate the mass of C2H2 and O2 that reacted from the balanced equation. This is illustrated below:
Molar Mass of C2H2 = (12x2) + (2x1)
= 24 + 2 = 26g/mol
Mass of C2H2 that reacted from the balanced equation = 2 x 26 = 52g
Molar Mass of O2 = 16x2 = 32g/mol
Mass of O2 that reacted from the balanced equation = 5 x 32 = 160g
Now, we can obtain the mass of C2H2 that will react with 68.1g of O2 as follow:
From the balanced equation above,
52g of C2H2 reacted with 160g of O2.
Therefore, Xg of C2H2 will react with 68.1g of O2 i.e
Xg of C2H2 = (52x68.1)/160
Xg of C2H2 = 22.13g
Therefore, 22.13g of C2H2 is needed to react with 68.1g of O2
Answer:
The theoretical yield of Cu(s) in moles is 60.15 moles
Explanation:
Step 1: Data given
Number of moles CuO = 70.8 moles
Number of moles NH3 = 40.1 moles
Molar mass CuO = 79.545 g/mol
Molar mass NH3 = 17.03 g/mol
Step 2: The balanced equation
3CuO(s) + 2NH3(g) → 3H2O(l) + 3Cu(s) + N2(g)
For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2
NH3 is the limiting reactant. It will completely be consumed (40.1 moles). CuO is in excess. There will react 3/2 * 40.1 = 60.15 moles
There will remain 70.8 - 60.15 = 10.65 moles CuO
Step 3: Calculate moles Cu
For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2
For 40.1 moles NH3 we'll have 60.15 moles Cu
The theoretical yield of Cu(s) in moles is 60.15 moles
Answer:
a)22.2°C after adding magnesium
b)17.3°C before adding magnesium
c) 4.9 is change
