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barxatty [35]
3 years ago
12

Dry air is 78.09% nitrogen, 20.95% oxygen, 0.93% argon, 0.039% carbon dioxide so varying amounts of water vapor- depending on hu

midity. Some gases however strongly absorb infrared radiation and trap it in the atmosphere and can therefore result in elevated global temperatures. Therefore they are termed greenhouse gases. Which greenhouse gas have we observed a marked increase in atmospheric concentrations in the last 100 years?
A. methane (CH4)
B. carbon monoxide
C. carbon dioxide
D.ozone (03)
E. oxygen
F. nitrogen
G.water vapor (H20)
Chemistry
1 answer:
AfilCa [17]3 years ago
5 0

Answer:

C. Carbon dioxide

Explanation:

Carbon dioxide is one of the end-product of combustion reactions involving many fuels today.

With the rapid increase in urbanization and technological development, man demand for energy increased tremendously. The discovery of fossil fuels paved the way for the astronomical increase in the concentration of carbon dioxide in the atmosphere. The burning of fossil fuels like coal and oil invovles the process where the carbon atoms present in these fuels combine with oxygen in the air to make CO2. This has resulted in an increase in the concentration of atmospheric carbon dioxide (CO2).

The burning fossil fuels for electricity, industry, heat, and transportation are the major sources of the emossion of carbon dioxide.

Also, the cutting down of trees for paper production, building construction and for the establishment of settlements also increase the concentration of carbon dioxide in the atmosphere. Trees are help remove carbon dioxide from the atmosphere through the process of photosynthesis. However, when these trees are cut down, carbon dioxide accumulates in the atmosphere.

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Consider the following chemical equation: NH4NO3(s)⟶NH+4(aq)+NO−3(aq) What is the standard change in free energy in kJmol at 298
Galina-37 [17]

Answer:

\Delta _rG=-4.3\frac{kJ}{mol}

Explanation:

Hello,

In this case, for the given dissociation reaction, we can compute the enthalpy of reaction considering the enthalpy of formation of each involved species (products minus reactants):

\Delta _rH=\Delta _fH_{NH^{4+}}+\Delta _fH_{NO_3^-}-\Delta _fH_{NH_4NO_3}\\\\\Delta _rH=-132.5+(-205.0)-(-365.6)=28.1kJ/mol

Next, the entropy of reaction considering the standard entropy for each involved species (products minus reactants):

\Delta _rS=S_{NH^{4+}}+S_{NO_3^-}-S_{NH_4NO_3}\\\\\Delta _rS=113.4+146.4-151.1=108.7J/mol*K

Next, since the Gibbs free energy of reaction is computed in terms of both the enthalpy and entropy of reaction at the given temperature (298.15 K), we finally obtain (two significant figures):

\Delta _rG=\Delta _rH-T\Delta _rS\\\\\Delta _rG=28.1kJ/mol-(298.15 K)(108.7\frac{J}{mol*K}*\frac{1kJ}{1000J}  )\\\\\Delta _rG=-4.3\frac{kJ}{mol}

Best regards.

6 0
3 years ago
What is the answers to these questions?
serious [3.7K]

2. B

3. B

4. A

5. C

6. B

4 0
3 years ago
A 3.20-mol sample of gas occupies a volume of 350. mL at 300.0 K. Determine the
nalin [4]

Answer:

P \approx 225atm

Explanation:

From the question we are told that:

Moles of sample n=3.20_mol

Volume V=350mL

Temperature T=300k

Generally the equation for ideal gas is mathematically given by

 PV=nRT

 P=\frac{nRT}{V}

 P=\frac{3.20*0.08206*300}{350*10^{-3}}

 P=225.079atm

 P \approx 225atm

4 0
3 years ago
What are
Vesna [10]

Answer:

carbohydrates

Explanation:

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7 0
3 years ago
Read 2 more answers
Cellular respiration involves the use of oxygencarbon dioxide and the release of carbon dioxideoxygen
Reil [10]
Cellular respiration can be thought of as the opposite of photosynthesis.  In cellular respiration oxygen is turned into carbon dioxide  while in photosynthesis carbon dioxide is tuned to oxygen.

I hope this helps. let me know in the comments if anything is unclear. 
3 0
2 years ago
Read 2 more answers
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