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pentagon [3]
2 years ago
7

Create a coordinate proof to show that the two triangles are congruent by the SSS Triangle Congruence Theorem.

Mathematics
1 answer:
jok3333 [9.3K]2 years ago
8 0

For a person to be able to create a coordinate proof to show that the two triangles are congruent by the SSS Triangle Congruence Theorem one can simply use the distance formula.

<h3>How can the distance formula prove SSS Triangle Congruence Theorem?</h3>

Given that the distance formula =

\sqrt{(x_{2} -x_{1})^{2}  + (y_{2} - y_{1}^{2}   )}

Let say that Angle ABC has the vertices of A (-4, -2),  B (-5,1). C (0,2) and Angle DEF   has the vertices of D (7, -4), E (4,-5), F (3,0)

So lets prove it:

AC = \sqrt{(x_{2} -x_{1})^{2}  + (y_{2} - y_{1}^{2}   )}

=\sqrt{(-4-0)^2 + (-2-2)^2}

=\sqrt{32}

= 4\sqrt{2}

Do the same for DF:

DF = \sqrt{(x_{2} -x_{1})^{2}  + (y_{2} - y_{1}^{2}   )}

= \sqrt{(7-3)^2 + (-4-0)^2}

=\sqrt{32}

= 4\sqrt{2}

Looking at the above, one can see the values are the same and as such this proves that AC is the same to DF. If you do the same for the other part of the angles, you will see that they are congruent.

Therefore, For a person to be able to create a coordinate proof to show that the two triangles are congruent by the SSS Triangle Congruence Theorem one can simply use the distance formula.

Learn more about congruent Angle from

brainly.com/question/2938476

#SPJ

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<h3>Answer:  C) 142 degrees</h3>

=======================================================

Explanation:

Extend segment MN such that it intersects side ST. Mark the intersection as point A. See the diagram below.

We're given that angle MNT is 72 degrees. The angle TNA is equal to 180-(angle MNT) = 180 - 72 = 108 degrees, since angles MNT and TNA add to 180.

For now, focus entirely on triangle TNA. We see from the diagram that T = 34 and we just found that N = 108. Let's find angle A

A+N+T = 180

A+108+34 = 180

A+142 = 180

A = 180-142

A = 38

So angle NAT is 38 degrees.

----------------------------

Since segment MA is an extension of MN, and because MN || SQ, this means MA is also parallel to SQ.

We found at the conclusion of the last section that angle NAT was 38 degrees. Angles QST and NAT are corresponding angles. They are congruent since MA || SQ. This makes angle QST to also be 38 degrees

----------------------------

The angles QSR and QST are a linear pair, so they are supplementary

(angle QSR) + (angle QST) = 180

angle QSR = 180 - (angle QST)

angle QSR = 180 - 38

angle QSR = 142 degrees

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