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dezoksy [38]
3 years ago
6

Look at this number line.

Mathematics
1 answer:
Lina20 [59]3 years ago
3 0
A it’s a I think ok because I’m new
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What’s wants to. answer my question what is 123465839274+384x384729+384=? <br> (Email)
Sunny_sXe [5.5K]

Answer:

123613575594

Step-by-step explanation:

3 0
3 years ago
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What is the solutions for x in the equation -2x+14+10x=34
san4es73 [151]

Answer:

x=2.5

Step-by-step explanation:

Put the like terms together, like so:

10x-2x=34-14

The result is this:

8x=20

Simplify to get:

x=2.5

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3 years ago
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I’m confused can someone explain?
Novay_Z [31]

Answer:

It is 150 percent

Step-by-step explanation:

You can find this value by dividing the numerator by the denominator, summing this value to the integer part and multiplying the result by 100%, so:

1 1/2 in percent = (1 + 1/2) × 100% =

(1 + 0.5) × 100% = 1.5 × 100% = 150%

Hope this helps! Sorry if I'm wrong.

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3 years ago
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The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.
tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}

so, it passes through the midpoint of AB,

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}

4 0
3 years ago
What is the y-intercept of a line that passes through the points (1, -7) and<br> (5,-25)?
ANTONII [103]

Answer:

-5/2

Step-by-step explanation:

i really hope this helps you out!

5 0
2 years ago
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