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dezoksy [38]
3 years ago
6

Look at this number line.

Mathematics
1 answer:
Lina20 [59]3 years ago
3 0
A it’s a I think ok because I’m new
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PLEASE I NEED HELP IF IT'S WRONG I WILL REPORT
Alinara [238K]

Answer:

what do you need help wth ?

Step-by-step explanation:

3 0
3 years ago
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Find x<br><br> A. X = 23<br> B. X = 31<br> C. X = 62<br> D. X = 118
Scorpion4ik [409]

Answer:

A

Step-by-step explanation:

6x-20= 118

6x= 118 + 20

6x = 138

x = 138/6

x= 23

8 0
3 years ago
The function f(t) = 5 cos(pi over 6t) + 7 represents the tide in Stanley Sea. It has a maximum of 12 feet when time (t) is 0 and
Juliette [100K]
The function for the height is
f(t) = 5cos( \frac{ \pi }{6} t)+7

f(0) = 5 cos(0) + 7 = 5 + 7 = 12  (verified)
The period is T  = 12 hours.

After 4 hours (t = 4), the height is
f(4) = 5cos( \frac{ 4\pi }{6} )+7 = 5*(-0.5)+7=4.5

A graph of f(t) confirms the answer.

Answer: 4.5 ft

4 0
3 years ago
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three sister are getting new outfits. shirts cost 11 each,skirts coat 25 each and shows cost 44 a pair what is the total coast o
MatroZZZ [7]

Answer:

240.

Step-by-step explanation:

Here is the correct question: Three sister are getting new outfits. shirts cost 11 each,skirts coat 25 each and shoes cost 44 a pair. what is the total cost of the new outfits for all of the sisters​?

Given: Cost of each shirt is 11

           Cost of each skirts coat is 25

           Cost of each pair of shoes cost is 44.

Now, finding total cost of shirt, skirt coat and shoes as cost of one new outfit.

= 11+25+44 = 80

∴ Total cost of one new outfit is 80.

Next, finding cost of new outfit for all, three sisters.

Cost of new outfit for three sister = \textrm { cost of one outfit}\times \textrm{ number of sisters}

∴ Cost of new outfit for three sister = 80\times 3= 240

240 is the total cost of new outfit for all the sisters.

         

3 0
4 years ago
The manager of a coffee shop has one type of coffee that sells for $7 per pound and another type that sells for $11 per pound. T
kirza4 [7]
More of the $7 coffee would be used<span />
3 0
3 years ago
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