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dezoksy [38]
3 years ago
6

Look at this number line.

Mathematics
1 answer:
Lina20 [59]3 years ago
3 0
A it’s a I think ok because I’m new
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Convert 15 yards per hour to inches per hour.
Serga [27]

Answer:

540 inches per hour!!

Step-by-step explanation:

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3 years ago
How do I get the frequency and number where do I start
dusya [7]

This good photo for your question

5 0
4 years ago
Decide which of the two points lies on the graph of the line.
Gwar [14]

Answers:

  1. B) (2,6)
  2. A) (4,2)
  3. B) (6,4)

===========================================

Explanations:

  1. For this problem, the x and y coordinates must add to 8. In choice A, we have x+y = 2+4 = 6, which doesn't work. But choice B does work since x+y = 2+6 = 8. Therefore, the point (2,6) is located on the line x+y = 8. The equation x+y = 8 is equivalent to y = -x+8.
  2. The x coordinate must be equal to 4. The y coordinate can be anything you want. The point (4,2) is on this line, while (2,4) is not. Another point on this line is (4,1). The line is completely vertical.
  3. If we plugged the x & y coordinates of choice A into the equation, we get 6 = 4-2 which then becomes 6 = 2 and that's a false statement. That rules out choice A. If we try choice B, then we get 4 = 6-2 which becomes 4 = 4. We get a true statement so choice B is the answer.
4 0
3 years ago
Select the three expressions that are equivalent to 3/5a + 10
Sonbull [250]

Answer:

A, C and D

Step-by-step explanation:

Given

\frac{3}{5}a + 10

Required

Select 3 equivalent expressions

\frac{3}{5}a + 10

Express 3 as 2 + 1

\frac{2 + 1}{5}a + 10

Rewrite as:

\frac{2a + a}{5} + 10

Split

\frac{2a}{5} + \frac{a}{5} + 10 ----- Option (A)

\frac{3}{5}a + 10

Express 10 as 14 - 4

\frac{3}{5}a + 14 - 4

Rewrite as:

14+\frac{3}{5}a  - 4 --- Option (C)

\frac{3}{5}a + 10

Factor out 1/5

\frac{1}{5}(3a + 50) --- Option D

7 0
3 years ago
Find the solution of this system of equations 10x-7y=-1 and -2x-7y=-25
Sergio039 [100]

Answer:

<h2>x = 2, y = 3 → (2, 3)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}10x-7y=-1\\-2x-7y=-25&\text{change the signs}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}10x-7y=-1\\2x+7y=25\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad12x=24\qquad\text{divide both sides by 12}\\.\qquad x=2\\\\\text{Put it to the second equation}\\2(2)+7y=25\\4+7y=25\qquad\text{subtract 4 from both sides}\\7y=21\qquad\text{divide both sides by 7}\\y=3

8 0
4 years ago
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