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Dovator [93]
3 years ago
8

A bank loans a customer $66,000 for a period of 5 years. the simple interest rate of the loan is 10.5%. what is the total amount

that the customer will need to pay the bank over the 5 years?
Mathematics
1 answer:
MArishka [77]3 years ago
6 0
66,000*0.15
9,900*5
49,500+66000
The answer is 115.500
I'm not sure if the whole thing is correct, but here is the easier way:
66,000(1+1.15)^5
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The measure of an angle in standard position is given. Find two positive angles and two negative angles that are coterminal with
Pani-rosa [81]
Notice the picture below

negative angles, are just angles that go "clockwise", namely, the same direction a clock hands move hmmm so....  and one revolution is just 2π

now, you can have angles bigger than 2π of course, by simply keep going around, so, if you go around 3 times on the circle, say "counter-clockwise", or from right-to-left, counter as a clock goes, 3 times or 3 revolutions will give you an angle of 6π, because 2π+2π+2π is 6π

now... say... you have this angle here... let us find another that lands on that same spot

by simply just add 2π to it :)  

\bf \cfrac{7}{6}+2=\cfrac{19}{6}\qquad thus\qquad \cfrac{7\pi} {6}+2\pi =\cfrac{19\pi }{6}
\\\\\\
\cfrac{19\pi }{6}\impliedby co-terminal\ angle

now, that's a positive one
and  \bf \cfrac{7}{6}-2=-\cfrac{5}{6}\qquad thus\qquad \cfrac{7\pi} {6}-2\pi =-\cfrac{5\pi }{6}
\\\\\\
-\cfrac{5\pi }{6}\impliedby \textit{is also a co-terminal angle}

to get more, just keep on subtracting or adding 2π


8 0
3 years ago
Which of these systems of linear equations has no solution?
Alika [10]

Answer:

A is correct

Step-by-step explanation:

A has no solution because since the slopes are the same, setting both equations equal to each other will cancel out the slopes and result in 8=16, meaning no solution will make both sides equal to each other.

B does have a solution because of different slopes

C does have a solution because of different slopes

D does have a solution because of different slopes

7 0
3 years ago
Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> In 2x - In(3x - 1) = 0
LenKa [72]

Answer:

\frac{-1}{3x^2-x}

Step-by-step explanation:

  1. If f(x) is in th form of f(x)=g(x)-h(x) then f'(x)=g'(x) - h'(x)
  2. When f(x)=z(g(x)) then f'(x)= z'(g(x))g'(x) (called as chain rule)

<u>using these information</u>:

g(x)=ln2x then g'(x)=\frac{(2x)'}{2x} =\frac{2}{2x}=\frac{1}{x}

h(x)=In(3x - 1) then h'(x)=\frac{(3x-1)'}{3x-1} =\frac{3}{3x-1}f'(x)=g'(x) - h'(x) =[tex]\frac{1}{x} - \frac{3}{3x-1} =\frac{-1}{3x^2-x}

7 0
3 years ago
Terminating vs. Repeating
Mila [183]
Thats uhm hard how u do that
8 0
3 years ago
A hypothesis _____.
Ivahew [28]
The answer is c. bc it doesn't need to be tested
7 0
3 years ago
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