CXB = 40 degrees
I am not positive but from what I have looked up this is the answer.
A tangent is always perpendicular to the radius at the point of tangency.
A right angle.
9514 1404 393
Answer:
(x, y) = (-1, -3)
Step-by-step explanation:
The equations are "consistent" and "not dependent." This will be the case whenever the ratios of x- and y-coefficients are different.
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We can solve this by "elimination" by multiplying the first equation by -4 and adding the result of the second equation being multiplied by 7.
-4(2x -7y) +7(7x -4y) = -4(19) +7(5)
-8x +28y +49x -28y = -76 +35 . . . . eliminate parentheses
41x = -41 . . . . . simplify
x = -1 . . . . . . . divide by 41
Using the second equation, we find y to be ...
(7x -5)/4 = y = (7(-1) -5)/4 = -12/4 = -3
So, the solution is (x, y) = (-1, -3).
<span>f x=0 ==>x^4+400=0+400=400</span>
Answer:
Step-by-step explanation:
Rewrite this quadratic equation in standard form: 2n^2 + 3n + 54 = 0. Identify the coefficients of the n terms: they are 2, 3, 54.
Find the discriminant b^2 - 4ac: It is 3^2 - 4(2)(54), or -423. The negative sign tells us that this quadratic has two unequal, complex roots, which are:
-(3) ± i√423 -3 ± i√423
n = ------------------- = ------------------
2(2) 4