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Marina86 [1]
2 years ago
11

Line AB contains points A (8,-4) and B (1, -5). The slope of line AB is

Mathematics
1 answer:
viktelen [127]2 years ago
6 0

Let, the points be A (8, −4) and B (1, −5). The slope of line AB exists 1/7.

<h3>How to estimate the slope of line AB?</h3>

Utilize the slope formula to estimate the slope of a line provided the coordinates of two points on the line.

The slope formula exists $m = (y_{2} -y_{1})/(x_{2}  - x_{1} ), or the difference in the y values over the difference in the x values. The coordinates of the first point symbolize $x_{1}and $y_{1}. The coordinates of the second points exist $x_{2} , y_{2} .

The slope of the line exists the ratio of the rise to the run, or rise separated by the run.

$m = (y_{2} -y_{1})/(x_{2}  - x_{1} )

The Line, AB contains points A (8, −4) and B (1, −5).

Substitute the value of points in the equation then we get

$m = (y_{2} -y_{1})/(x_{2}  - x_{1} )

m = (-5-(-4))/(1 - 8)

Simplifying the above equation, we get

m = (-5+4)/(1 - 8)

m = (-1)/(-7)

m = 1/7

Therefore, the slope of line AB exists 1/7.

To learn more about the slope of the line refer to:

brainly.com/question/2410369

#SPJ9

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Fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.

Step-by-step explanation:

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Area of figure=ar(1)+ar(2)+ar(3)

Area of region 1 = ar(ANGI)+ar(AIB)

                          =L\times B+\frac{1}{2}\times base\times height\\\\=[1500\times (5000-2000-1500)]+\frac{1}{2}\times (3000-1500)\times (5000-2000-1500)\\\\=3375000m^2=337.5ha

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Let the fencing be done through x m downward from B which divides the two into equal area.

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⇒ar(ANGB)+ar(GKLB)=ar(KLCM)+ar(MDCF)\\\\337500+3000x=(3500-x)\times 1000+2000(1500-x)\\\\3375000+3000x=3500000-1000x+3000000-2000x\\\\6000x=315000\\\\x=\frac{315000}{6000}=520.8m

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